/sci/ - Science & Math

I don't feel like solving it but I'll help you improve your chances of getting someone else to.

no, read the rules

Did you just write
>fp = f prime = df/dn
because you couldn't find the ' symbol!?

Also, your question doesn't have a general solution.

I'm curious as to how you'd do this. Looks like some chain rule shit.

starts to repeat at some point when trying to solve with integration by parts. I'll just see if I can move from there and share the result here for curious people!

and I didn't know there were symbols here, as said, newbie :)

This is how you would write it you fucking neandrathal. Are you really too lazy to google the integral ascii symbol and too dumb to write ' instead of p?

∫f'(n)(1 - f'(n))dn

As for how to solve it, idk lol. Maybe distribute it it out like this:

∫[ f'(n) - f'(n)f'(n) ]dn

And use integration by parts for the second term?

>>6929469
*p instead of '

>>6929455
reported for shitposting

well, it repeats but it is kinda a tough one. here's what I've got so far

>>6929469
man I love you!

thanks :)

p.s. solution in the image

>>6929521
too early to celebrate, meh. that gives 1=1 when simplified :/

>>6929521
Doesn't that just leave ∫f'(n)dn = f(1-f'(n)) + f(n)f'(n) instead of the original integral?

And shouldnt ∫f'(n)dn just be f(n) anyways?

>>6929489
reported for announcing reports

>>6929592
reported for announcing reports

>>6929652
reported for announcing report of post announcing report