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/sci/ - Science & Math


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6642261 No.6642261[DELETED]  [Reply] [Original]

As the area under an acceleration-time graph is equal to velocity at a given time and the area under a velocity time graph is equal to displacement at a given time, can anyone explain what the area under a displacement time graph equals?

>> No.6642262

Nothing. Not every pattern goes on forever bro.

>> No.6642264

>>1763691
Displacement * time

>> No.6642342

Let's think critically for a second.

In MKS,

acceleration = <span class="math">\displaystyle \frac{m}{s^2}[/spoiler]

<span class="math">\displaystyle \frac{dv}{dt} = 1 \frac{m}{s^2} \,\,\, \Rightarrow \,\,\, \int dv = \int 1 dt \,\, \frac{m}{s^2} [/spoiler]

So,

<span class="math">\displaystyle v = t\, s*\frac{m}{s^2} \,\,\, \Rightarrow \,\,\, t \, \frac{m}{s}[/spoiler]

Repeat this process,

<span class="math">\displaystyle \frac{dx}{dt} = t \, \frac{m}{s} \,\,\, \Rightarrow \,\,\, \int dx = \int t \, dt \frac{m}{s}[/spoiler]

<span class="math">\displaystyle x = t^2 \, s*\frac{m}{s} \,\,\, \Rightarrow \,\,\, x = t^2 m[/spoiler] (meters)

So if the pattern continued, we'd have m*s (meters times seconds)

In terms of measurable quantities, it's a little hard to imagine.

>> No.6642602

>>6642261
I'd like to suggest the name "bias"

the longer the displacement is not equal to 0, and the further it gets from 0, the bigger bias is.
Likewise, if positive and negative displacement compensate each other, there is no bias. You can have positive or negative bias. And just like for a politician, the current position of the point is given by the variation in their bias. Where is my Nobel Prize ?

(idea came to me from robotics and stats courses)

>> No.6643207

think of it as "loneliness"

imagine your family send you to summer camp, 5 miles away, for 6 months. you have a loneliness of 30month-miles.

imagine you travel from your friends house to your house. every 5 minutes, note your distance from your friend and multiply it by 5. the sum is an approximation of your exact loneliness.
subsitute 5 minutes for 4 seconds to be more exact. substitute 4 seconds with 0.001 seconds. ect. obviously a limit would help. if you wrote out said limit, it would show the integral reimannsum definition.

>> No.6643237

>>6642602
It's already called absement sorry

It's also completely useless