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6327647 No.6327647[DELETED]  [Reply] [Original]

A bottle of concentrated aqueous sulfuric acid, labeled 98.0 wt% H2SO4, has a concentration of 18.0 M.
How many milliliters of reagent should be diluted to 1.600 L to give 2.00 M H2SO4?

My solution:
2M= x/1.6L -> x= 3.2mol.
18M= 3.2mol/v -> v= 3.2mol/18M -> v= .178L = 17.8mL.

What am I doing wrong? According to the website, this is not the correct answer. Thanks.

>> No.6327672

Bump

>> No.6327724

anyone?

>> No.6327732

>>6327647
18x = 1.6 * 2

>> No.6327738

>>6327732
that gives x= 17.8 mL. Which is wrong. Which is what OP did (x=3.2/18).

>> No.6327747

>>6327738
It gives 178ml

>> No.6327753

>>6327747
By god I'm a fucking moron.

>> No.6327751

>>6327647
0.178L is 178ml NOT 17.8

>> No.6327759

c1v1=c2v2
v1=(c2v2)/c1
v1=(1.600L*2.00M)/18.0M
v1=0.178L
v1=178mL
Goddamn it I did the whole question before noticing that all you fucked up is the unit conversion. 0.178L=178mL

>> No.6327762

>>6327647
1.6L of 2M solution...
solution holds 3.2M
18M reagent
3.2 / 18 = .178
total = 1.6
x + .178 =1.6
x = 1.422

so 1,422 ml of water + 178 ml of 18M acid = 1.6L of 2M reagent