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/sci/ - Science & Math


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File: 41 KB, 360x613, aaaa.jpg [View same] [iqdb] [saucenao] [google]
6043172 No.6043172 [Reply] [Original]

So here's the situation.
In the first picture, you have a block of wood, perfectly rectangular bases. In the second picture you drop said block of wood in a windless enviornment that DOES have air resistance. You than measure the force of the air resistance at certain times and speeds.

Here's where it gets good. In the third picture you drop a block with the exact same composition as well as the same mass and density (the volume is decreased vertically to compensate, this in no way affects air resistance). This block is rotated at some angle like so. The distance that it spans horizontally is the same as the first one, despite rotation. What affects will this have on the forces produced by air resistance as it falls. Assume that the block will not rotate (or if it does rotate, will the sum of the forces that make it rotate and slow down be equal to that of the first example? If so, what portion will be rotational force?)

Thank you.

>> No.6043174
File: 9 KB, 459x377, reaction frown.png [View same] [iqdb] [saucenao] [google]
6043174

>>6043172
hahahahahahahahahaah step 2 looks like this face ahahahahaahahahahahahahaha

>> No.6043294
File: 753 B, 153x25, 99a6015b6a230860c9b1517b238e5de9[1].png [View same] [iqdb] [saucenao] [google]
6043294

Equation for Force due to drag. A is the cross sectional area of the object. Though practically the situation would not work like this, in your hypothetical, it would have the same cross section (distance 'x').

>> No.6043302

Alright. Thank you.