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/sci/ - Science & Math


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5996322 No.5996322 [Reply] [Original]

What is the real answer, if there is one, to 0/0?

>> No.5996324

undefined

>> No.5996328

>>5996322

infinity because they are both unlimited 'numbers'

>> No.5996334

>>5996324
>>5996328

So uh, what is it?

>> No.5996337

>>5996334

It's undefined. >>5996328 is just doing a lel so funneh meme.

>> No.5996351

1

>> No.5996354

0=0
0/0=0/0
1=1

>> No.5996355

>>5996324
You mean indeterminate form.

>> No.5997356

x = 0

x/x = 1
0/x = 0
x/0 = infinity

1 = 0 = infinity

>> No.5998103

0/0 = 0^1 * 0^-1 = 0^0 = 1

>> No.5998891

>>5996324
"undefined" is not an answer

>> No.5998909

>>5998891

Sure it is.

>> No.5998957

>>5998891
Absolutely is.

>> No.5999546

Everything you want it to be

>> No.5999568

you have 0 candies and 0 kids, so no candies to any kid.
Answer is 0.

>> No.5999585
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5999585

a/b is the answer x to the equation a = bx

eg 21/3 is the answer to 21 = 3x

so what answers 0 = 0x ? x can be any and every number, so we say it is undefined

>> No.5999600

I think about it like this: I threw none of the snowballs I didn't have. I hate my dad; I threw all of the snowballs I had, which was none, which means an absolute action, so if you're plotting an absolute action on a graph it means ALL values, so a vertical line.

>> No.5999603

>>5996322

0/0 is undefined.

There are many functions with denominator values that can approach zero, when the denominator's value becomes zero however those functions' value could approach anything.

In other words when one function's denominator becomes zero that function might approach 1. At the same time a different function might approach 2, or 3, or any other number. When we say that 0/0 is undefined we mean to say that it could represent any value.

many functions that represent physical phenomenon actually do evaluate to 0/0 at some point and at those points the correct answer for the function is determined by its limit as it approaches whatever value makes it evaluate to 0/0.

>> No.5999652
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5999652

>>5996354
lel

>> No.5999672

>>5996322
Look, it's this thread again...

>> No.6000130

0/0 = lim a->0 (a/a) = lim a->0 (1)= 1

>> No.6000151

>>>6000000

>> No.6000182

use L'Hospital and discover for yourself

>> No.6000216

>>5999600
But that is 0/1.

>> No.6001818

>>6000216
No, that's 1/0.

>> No.6002706

1/1=1 3/3=1 8/8=1 1/4=.25 so in terms of ratio, 0/0=1

>> No.6002748

>>5996322
indeterminate form

our way of saying its nonsensical, no solution, undefined

not everything has an objective answer

>> No.6002751

>>6002706
no

>> No.6002770

>>6002706
0/3, 0/2, 0/1, 0/0 all have the same ratio

>> No.6002787

>>6002770
Not the same ratio

>> No.6002858
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6002858

>The function (x,y) -> x/y
It is defined for any x and for y=/=0
Nowhere can in be extended continuously.
In particular, it is not and cannot be defined at (0,0).

>> No.6002865

>>5996322
It is of indeterminate form in normal algebras. But you can always abstract it by creating a field with extra elements and defining division as unary.

>> No.6002866

>>5999568
This is not how real maths works. That's childish elementary school crap.

>> No.6002891

>>6002865
Nope. In any non-trivial ring (and a fortiori algebra), the neutral element for addition (or 0 element), cannot have an inverse.

Because for all x in that ring:
0*x = (1+(-1))*x (definition of an additive inverse)
0*x = 1*x + (-1)*x (distributivity)
0*x = x + (-x) (denition of multiplicative identity)
0*x = 0 (definition of additive inverse)
0*x =/= 1 (non-trivial)
x is not an inverse of 0

>> No.6002906

pretty sure its zero

how many times can u put zero into zero


well duh its zero cause u can't put anything into nothing, so it never happens


thank me later obama

>> No.6002918
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6002918

>>6002906
Leave /sci/ now and never come back

>> No.6002948

I wouldn't look for the real answer, but if you compactify the reals, then a reasonable answer is infinity.

>> No.6003110

>>6002948
No, it's any more reasonable than any other real.
Let f : (x,y) -> x/y
For any a and b (a*t,b*t) -> (0,0) and f(a*t,b*t) -> a/b =/= infinity in general, so your proposed extension doesn't make f continuous.

>> No.6003126

smegle/smegle=0/0 because smegle is the ULTIMATE loser. the penultimate loser is samwise gamgee. o wait, reverse!

>> No.6004161

>>6003110
Who cares about continuity?

>> No.6004195

The result you find depends on the path you take.

>> No.6004200
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6004200

If I'm not wrong, it'd be -∞<x<∞
so undefined

>> No.6004985

There is no answer because a fraction is another form of dividing and you cannot divide anything by 0

>> No.6005006

>>5999585
>that image
That's not fair, that's not the whole story, now show how many military bases Iran has around the US

>> No.6006401

By definition division is the inverse of multiplication.

0/0 = 0 * 0^-1 = 1

>> No.6007439

>>6006401
Zero has no inverse.

>> No.6008463

>>6005006
none

>> No.6010157

the only correct answer is 1

>> No.6011954

Let x = 1/0.

0/0 = 0 * 1/0 = 0 * x = 0

>> No.6013546

>>6011954
Let x = 0

0/0 = x/0 = infinity

>> No.6015694

>>6013546
Let x = 0.

0/0 = x/x = 1

>> No.6015751

>>6015694
Let x = 0

0/0 = 0 * 2/0 = x * 2/x = 2

>> No.6015771

>>5996322
Every possible number is a solution to 0/0

>> No.6015782

m = n/k
k*m = n
k = m/n
if k is 0
then m is 0

>> No.6017432

>>6015751
Let x = 0

0/0 = 0/(0*2) = 0/0 * 1/2 = x/x * 1/2 = 1 * 1/2 = 1/2

>> No.6019251

>>6015782
What if n is zero?

>> No.6019273

>>6015782

You cant rearrange for shit.
m = n/k
k*m = n
k = n/m

k and n = 0, m = any possible number