/sci/ - Science & Math

pls respond

bump

x*u(x)

with u(x) being the heaviside function

Your function isn't smooth (continuous in the first derivative). The simplest function with your behavior is the explicit description which you're saying:
f(x) = 0 for x \leq 0
f(x) = x for x \geq 0

(where \geq and \leq mean "greater/lesser than or equal to), or, equivalently, x Θ(x), where Θ(x) is the Heaviside step function.

>>5641247
thanks man

looks like heaviside functions use conditions as well

anyway thanks for the help guys

<span class="math">\frac{\sqrt{x^2}+x}{2}[/spoiler]

>>5641270
Perfect.

>>5641270
ARE YOU A WIZARD

sqrt(3)

>>5641270
Now is there one that returns 0 for all negative numbers and from 0 to 5?

- not OP

>>5641292
And behaves linearly for all other input

Set function to = zero

>>5641292
<div class="math">\frac{\sqrt{(x-5)^2}+x-5}{2}</div>

>>5641297
That turns out to be x-5

Doesn't work

>>5641299
Unless you take the negative root, which turns the top to 0 for all numbers. Which still doesn't work...

>>5641299
>>5641302
Never mind, I'm retarded.

>>5641297
Oh god, why does this work. This one >>5641270
makes more sense just looking at it since it works out algebraically but this one >>5641297 looks like it would become \frac{2(x-5)}{2} or \frac{-(x-5)+x-5}{2}

\frac{\sqrt{(x-5)^2}+(x-5)}{2}

>>5641270
<span class="math"> \sqrt{x^2} = |x| = \mathop{\rm sgn}(x) x[/spoiler] for all <span class="math">x \in \mathbb{R}[/spoiler].

>>5641330
Replacing x with x-5 moves the whole thing 5 to the right.

>>5641408
>Replacing x with x-5 moves the whole thing 5 to the right.
Um, okay.