/sci/ - Science & Math

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Anonymous Thu Mar 21 00:55:33 2013 No.5626468 [Reply] [Original]

Its a Maximum power transfer in Dc circuit.
My Prof told me to finish the data, but I don't
know how to. Can you guys help?
tl;dr help me finish the data

>>	Anonymous Thu Mar 21 01:00:49 2013 No.5626475 don't do it op

>>	Anonymous Thu Mar 21 01:05:32 2013 No.5626479 bump

>>	Anonymous Thu Mar 21 01:10:18 2013 No.5626486 help me guys pls

>>	Anonymous Thu Mar 21 01:15:33 2013 No.5626491 trying to understand your drawing is making me feel retarded

neckbeard_the_pirate Thu Mar 21 01:43:48 2013 No.5626547

I'm slightly confused here. Schematic "A" has a 150 and a 100 ohm resistor. Are they floating or connected to -18V? According to the question on the paper, "Rl" is equivalent to the resistor network on the top of the page. If you find out what this combined resistance is, the rest is just Ohm's Law, assuming when he asks for the "V,I, and P" of "Rl". The value of the resistor network for "A" is about 54.9933 ohms. The value of the resistor network for "B" is about 199.9007 ohms.

>>	Anonymous Thu Mar 21 01:47:48 2013 No.5626555 >>5626547 conected sorry got the crappy drawing

>>	neckbeard_the_pirate Thu Mar 21 01:51:04 2013 No.5626565 >>5626555 It's just Ohm's Law. The only thing you could be confused about is how to simplify the resistors in the circuit. Is there any specific part that confuses you? Are you confused as to where you start?

>>	Anonymous Thu Mar 21 02:02:19 2013 No.5626576 >>5626547 Not OP. From what I'm seeing, above and below A are supposed to be the same circuit, and the bottom one is showing where RL would connect. And I'm getting a much different value for the resistance of circuit A.

>>	neckbeard_the_pirate Thu Mar 21 02:05:47 2013 No.5626581 >>5626576 I still get 54.9933 ohms. I'm doing the top circuit, the one without the battery. Also, OP said the lower circuit is misdrawn and the two resistors are really connected to -18V.

>>	neckbeard_the_pirate Thu Mar 21 02:08:32 2013 No.5626586 >>5626576 Oops. Should have added in how I calculated it: ((220 \|\| 150)+(33)) \|\| 100 220 \|\| 150=89.1892 89.1892+33=122.1892 122.1892 \|\| 100=54.9933

>>	Anonymous Thu Mar 21 02:20:33 2013 No.5626604 >>5626586 love you

>>	Anonymous Thu Mar 21 02:21:33 2013 No.5626605 >>5626586 Ok I recalculated it seeing it from A -> B and got 54.99. I thought that OP just messed up the bottom drawing and that the 150 and 100 were supposed to still be connected, and that the current starting flowing before 220.

>>	neckbeard_the_pirate Thu Mar 21 02:26:33 2013 No.5626611 Is OP still here?

>>	Anonymous Thu Mar 21 02:32:47 2013 No.5626618 >>5626611 i assumed he was >>5626604

>>	Anonymous Thu Mar 21 02:45:48 2013 No.5626627 >>5626618 still here

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