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/sci/ - Science & Math

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5477496 No.5477496 [Reply] [Original]

Wassup /sci/

Given: p - 2 = x; p = 18 - 3x

I know that x = 4

Now how do I determine the coordinates of the market equilibrium point algebraically.

And how do I graph each pair on one set of coordinate axes, indicating the market equilibrium point.

>> No.5477507

no idea, but p = 6

>> No.5477511
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5477511

>>5477507
Thanks.

>> No.5477520

Couldn't you just graph them as basic linear equations? I may have missed something, but I have a feeling you're just over-thinking it.

>> No.5477524
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5477524

>>5477520
I think you are right.

But then, how do I determine the coordinates of the market equilibrium point algebraically.

>> No.5477532

>>5477524
uhh, its been a while since I've done this shit, but wouldn't it just be (x,p)?

Somebody please correct me if I'm wrong

>> No.5477563
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5477563

Teeth Bump

>> No.5477627
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5477627

wut

>> No.5477637

>>5477496
I think it's:
If p=18-3x
P=18-3(p-2)
P=18-3P-6
4P=24
P=24/4
P=6

Therefore if (6)-2=x, 4=x
P=6, x=4

>> No.5477645
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5477645

>>5477637
What about the graph

>> No.5477668

>>5477645
Horizontal line on p(6)
Vertical line on x(4)

>> No.5477677
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5477677

>>5477668
Mfw:

*graph a point and find equilibrium*