[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

View post   
File: 4 KB, 300x300, PolynomialPosEven.gif [View same] [iqdb] [saucenao] [google]
5154880 No.5154880[DELETED]  [Reply] [Original]

I've stumbled upon a problem, it seems i lack the knowledge of how to transform ploynomials, here is the example

p(x)=-1(x-1+i)(x-1-i)(x+2)(x-4)
and the transformation
p(x)=x^4-10x^2-20x-16

>> No.5154888

This is your second polynomials homework thread today.

>> No.5154932

>>5154888
I kno, it's kinda urgent, the test is tommorow

>> No.5154960

bumpies

>> No.5155017

Anyone, please?

>> No.5155026

bumpin'

>> No.5155027

what are you supposed to even do?

>> No.5155042

i'm supposed to transform p(x)=-1(x-1+i)(x-1-i)(x+2)(x-4) into p(x)=x^4-10x^2-20x-16, but i don't know the procedure

>> No.5155049

>>5155042
try wolfram alpha. idk what you mean by 'transform'. what class is this for?

>> No.5155081

Multiply like a crazy motherfucker.

But, I'll assume the "Transforming" is Pre-calculus mumbo-jumbo.

Alright, just remember Vertex Form. F(x) = A(x-h) + K And you'll be completely fine.

Say you wanted to move a graph 2 units to the left, and 3 units upwards. Your equation would thus be f(x)=A(x+2)+3

Next time, try not to ask the 4chan community. Some aren't as merciful as myself.

>> No.5155087

>>5155049
Math.

This is the same polynomial written in two different forms, i don't know how to jump betweent those two forms

>> No.5155099

>>5155087
>>5155087
>>5155087
>>5155087
>>5155087

Have you considered that maybe terms are all factors? SO MULTIPLY IT. FOR THE LOVE OF ALL THINGS ARITHMETIC STUDY FOR THAT GODDAMN TEST.

>> No.5155102

>>5155081
Thanks, but can you elaborate a little bit or are you maybe familiar with another method because i think we didn't use this aproach

Gonna take a power nap, then a long night of studying ahead of me, keep the suggestions comin', you're a lifesaver :)

>> No.5155114

>>5155102

Okay. well, these are all factors of the given Polynomial. Think about it, these are your x-intercepts. Your x-Intercepts are X= 1-i, 1+i, -2, and +4. But this makes me wonder, have you given us the right graph?

>> No.5155123

>>5155114
This is what the teacher has given us, even if the graph isn't correct I still don't know how to convert... Can you explain it with out the example?

>> No.5155122

>>5154880
>>5155102

Anyways, note the Complex Conjugate Theorem. Any complex zero, must have an opposite. Example: If one of my factors is (x+i) , I know immediately that another factor should be (x-i). Note: THIS ONLY WORKS FOR COMPLEX CONJUGATES.

But to answer your question, you multiply everything. Transforming isn't hard. That's all it really is. Multiplication.

>> No.5155132

>>5155099
>SO MULTIPLY IT. FOR THE LOVE OF ALL THINGS ARITHMETIC STUDY FOR THAT GODDAMN TES

That would take too much time, isn't there a shorter and simpler way?

>> No.5155141

>>5154880
>>5154880


So recap, Your first given equation is merely the polynomial in factored form. If you need to know your x intercepts, replace Y with 0, and solve.

Example: 0= (x+3)(x-5)
This means (x+3)=0, and (x-5)=0. Through some simple subtraction, one can easily discern that x= -3, and x=5. Those would both be your X-intercepts in the given graph.

>> No.5155148

>>5155132

I wish there was, man. There is no simpler method. Aside from using a graphing calculator, I'd say you're out of luck.