/sci/ - Science & Math

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Anonymous Mon Sep 17 13:12:30 2012 No.5065876 [Reply] [Original]

just a little more help....thanks guys

>>	Anonymous Mon Sep 17 13:14:00 2012 No.5065879 bump

>>	Anonymous Mon Sep 17 13:15:15 2012 No.5065883 i made the thread about finding the dimensions

>>	Anonymous Mon Sep 17 13:16:44 2012 No.5065890 please guys

>>	Anonymous Mon Sep 17 13:18:14 2012 No.5065894 last bump

>>	Anonymous Mon Sep 17 13:26:45 2012 No.5065918 You're not even trying, show what you have tried with it and I might consider thinking of maybe helping you.

>>	Anonymous Mon Sep 17 13:31:00 2012 No.5065924 >>5065918 so far I got 48y^4+x(3y^3/1). I know im way off

>>	Anonymous Mon Sep 17 13:34:15 2012 No.5065934 >>5065924 Would it help if I told you that sqrt(48yx^2) = sqrt(48)sqrt(y)sqrt(x^2), also 48=3*16

>>	Anonymous Mon Sep 17 13:38:00 2012 No.5065949 >>5065934 you're talking to a math illiterate. I've written down what you just typed on paper and I have no idea what to do from there.

>>	Anonymous Mon Sep 17 13:39:59 2012 No.5065953 >>5065934 do im guessing from there I just factor or something..?

>>	Anonymous Mon Sep 17 13:43:59 2012 No.5065967 sqrt(48)=sqrt(3)sqrt(16)=4sqrt(3) sqrt(x^2)=x sqrt(y)=sqrt(y) so you are left with y4sqrt(3)xsqrt(y)=y4xsqrt(3y) xsqrt(3y^3)= xysqrt(3y) so in the end you have 4xysqrt(3y)+xysqrt(3y) that i'm sure you can simplify

>>	Anonymous Mon Sep 17 13:52:44 2012 No.5065986 File: 8 KB, 274x356, Unbenannt.png [View same] [iqdb] [saucenao] [google] 5 x y sqrt(3 y)

>>	Anonymous Mon Sep 17 13:53:59 2012 No.5065989 >>5065967 where else is there to simplify? Its not an equation so I cant just do the sqrt(3y)s on each side

Anonymous Mon Sep 17 13:57:44 2012 No.5065994
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OK I think i got that one. Now I am on this one here. I am thinking its just 2u^2y/y+.20^3u/x or something like that? Give me a sec to work it out on paper; that was just in my head

TenchiMuyo1984 Mon Sep 17 13:58:45 2012 No.5065996

i got

y*sqrt(48*y*x²) + x*sqrt(3*y³)
sqrt(48)*sqrt(y³)*sqrt(x²) + x*sqrt(3)*sqrt(y³)
sqrt(4)*sqrt(4)*sqrt(3)*sqrt(y³)*x + x*sqrt(3)*sqrt(y³)
2*2*sqrt(3)*sqrt(y³)*x + x*sqrt(3)*sqrt(y³)
x*sqrt(3)*sqrt(y³) * ( 4 +1 )
x*sqrt(3)*sqrt(y³)*5

finish

or one of this:

5*x*sqrt(3*y³)
5*x*sqrt(3)*sqrt(y³)
5*x*3^(1/2)*y^(3/2)
5*x*3^(0.5)*y^(1.5)

>>	TenchiMuyo1984 Mon Sep 17 14:02:14 2012 No.5065999 >>5065994 16u^6 / ( 8u^4y + 30u³x ) 16u^3 / ( 8uy + 30x ) 8u^3 / ( 4uy + 15*x )

>>	Anonymous Mon Sep 17 14:05:29 2012 No.5066009 File: 5 KB, 209x241, Unbenannt.png [View same] [iqdb] [saucenao] [google] >>5065999 It's 20 instead of 30.

>>	Anonymous Mon Sep 17 14:05:45 2012 No.5066010 >>5065999 Actually it's 4u^3/(2uy+5x)

>>	Anonymous Mon Sep 17 14:06:44 2012 No.5066013 File: 3 KB, 227x215, Capture.png [View same] [iqdb] [saucenao] [google] >>>5065999 thanks. and what about this? Do I just simply divide every matching part?

>>	Anonymous Mon Sep 17 14:08:59 2012 No.5066014 >>5066010 >>5066009 damnit i already wrote down all that work and inputted the answer. oh well

>>	TenchiMuyo1984 Mon Sep 17 14:14:59 2012 No.5066024 >>5066009 Damn .... u allright ... xD >>5066013 3/(x+2) +1/2

>>	Anonymous Mon Sep 17 14:16:29 2012 No.5066031 OK quiz over. Thanks guys. Guess I should delete this thread unless someone wants to take it over for another topic or something..

>>	Anonymous Mon Sep 17 14:24:44 2012 No.5066056 sqrt(51y^3x^2)

>>	Anonymous Mon Sep 17 17:49:14 2012 No.5066725 That's a hard one, OP. I'll look into it.

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