/sci/ - Science & Math

You have to write that between [m@th][/m@th]

multiply it by n^2, then sun it with itself backwards:

top line: x + (x - 1) + (x - 2) + ... + (x - x + 1) + (x - x)
botton line: (x - x) + (x - x + 1) + (x - x + 2) + ... + (x - 1) + x

if you sum the series in the top with the bottom, then notice that if you group it by terms:

[x + (x - x)] + [(x - 1) + (x - x + 1)] + ... [(x - x + 1) + (x - 1)] + [(x - x) + x]

Cancelling out: x * (x + 1) (x terms or however many you have)

Then do x * (x + 1) / 2 (for one line) and you get:

x^2 + x / 2n^2

Therefore if x -> inf, that will go to inf too.

d'oh i meant
[m@ath]{{ x+(x-1)+(x-2)...+(x-x)}\over x^2 }; x \to ∞[/m@ath]

my bad dunno why i wrote that T_T

d'oh i meant
[m@ath]{{ x+(x-1)+(x-2)...+(x-x)}\over x^2 }; x \to ∞[/m@th]

my bad dunno why i wrote that T_T

d'oh i meant
[m@th]{{ x+(x-1)+(x-2)...+(x-x)}\over x^2 }; x \to ∞[/m@th]

my bad dunno why i wrote that T_T

>>4864720
the @ was meant as an 'a' obviously..

<span class="math">{{ x+(x-1)+(x-2)...+(x-x)}\over x^2 }; x \to ∞[/spoiler]

>>4864742
use \infty for a better infinity sign

sry ^^" i'm kinda new here

>>4864783
np, if you're into math and taking the effort to learn LaTeX, your presence is incouraged.