/sci/ - Science & Math

OP here

found the answer on Chegg

Don't have an account
http://www.chegg.com/homework-help/questions-and-answers/relaxed-spring-sitting-horizontal-surface-b
lock-attached-ends-kicked-horizontal-velocity-v-q2477659

anyone have a chegg account?

bump

the force acts radially
-> conservation of angular momentum, nigger

Just use newton's equation for each block, find the function for the x(t) solving the diff eq. And derivate that and find which is the maximum position for the block.

(1/2) mv^2/r = -kx
r = l0 + x
(1/2) mv^2/(l0 + x)
x = the distance it stretches.
fuck i graduated this morning and got drunk after so i have no clue.

>>4630091
>each block
>implying there's more than one

read the fucking question again

>>4630099
nigger #2 appears

>>4630108
thats mean

>>4630108
Well I misread, same idea. You have the force given by the spring which is radial... using a polar co-ordinate system this should be really easy.

>>4630110
You're right, that was completely uncalled for. Sometimes I get carried away with the general animosity of this board and I tend to engage in insulting and cruel behavior without regard for the mental anguish it may cause the more sensitive browsers of this board. I humbly ask that you accept my apology, nigger.

>>4629670
No, you don't need any of that fancy angular momentum. Conservation of energy is getting you nowhere because you have two unknowns, right? <span class="math">v_2[/spoiler] and <span class="math">x[/spoiler]. Well, the answer is to find <span class="math">v_2[/spoiler] first. If you use

<span class="math">F = mg + kx = m \frac{v_{2}^2}{L+x}[/spoiler]

you find

<span class="math">(mg + kx) (L+x) / 2= \frac{1}{2} m v_{2}^2[/spoiler]

Sub this in the conservation of energy and you should get a quadratic with only <span class="math">x[/spoiler] as the unknown. It's boring as fuck to expand and then group, but it's straightforward.

>>4630134
>using gravity
>missed the part about the motion being in a horizontal plane

two unknowns: v2 and x
two constraints: conservation of energy and conservation of angular momentum

deal with it

>>4630153
Well, yeah, I missed that. But I gave you the answer to a completely different problem. That's gotta count for something, right?

NO IT WON'T I NEED TO ANSWER THIS ONE TO STOP FEELING THE SHAME IN MY VEINS

<span class="math">v_1 l_0= v_2 (l_0 + x)[/spoiler]

<span class="math">\frac{1}{2} m v_{1}^2= \frac{1}{2} m v_{2}^2 + \frac{1}{2} k x^2[/spoiler]

It reduces to a third-order polynomial. Fuck this gay world.

Man I'm dumb. I don't understand why v_2 wouldn't be 1 m/s and x wouldn't be zero.