[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math


View post   

File: 28 KB, 525x323, halp.jpg [View same] [iqdb] [saucenao] [google]
4497253 No.4497253 [Reply] [Original]

Help me out here /sci/. I know how to do this with a given Standard deviation and mean but this function is throwing me off now.

Usually I just plug in the numbers into my calculator function: "normalcdf("

>> No.4497271

Am I going about it the wrong way? Do I even need to worry about the function?

>> No.4497279

You can find parts A and B pretty easily if you integrate the function. I never took a probability and stats course though, so off the top of my head I don't know the "correct" way to solve it.

>> No.4497282

teh probality of you faling youre math course reaches 101%

>> No.4497290

>>4497282
Yeah that's what I concluded when I got a 15/100 on my first test. Still trying though.

>> No.4497297

>>4497279
This. Here are the answers, OP, you can check your work at least:
A. 1/2 or 50%
B. 7/16 or 43.75%
C. 0 or 0%, only one I didn't just integrate for, solved by the logic of there being an infinite number of possible values for X between 0 and 2, so the probability of it being exactly 1.5 is 1/inf, which of course goes to 0. I don't remember what theorem/postulate that is, but whatever.

>> No.4497307

>>4497297
Thanks yo, though 50% for A seems to be wrong. B and C are correct though

>> No.4497309

>>4497297
For part C, you could take the even simpler logic that the highest value X can be when x>0 is 1, so it can never equal 1.5 at all.

>> No.4497310

>>4497307
Oh, fuck, integrated wrong, sorry, was bothering to write it out. 1/4.

>> No.4497312

>>4497307
A is 1/4

If you integrate it from 1 to 2.

>> No.4497319
File: 27 KB, 440x246, zscore.jpg [View same] [iqdb] [saucenao] [google]
4497319

>>4497312
>>4497310
Yeah that did the trick. Thanks a lot gentlemen.
Now does anyone know what the fuck this question is asking?

>> No.4497326

>>4497319
My bad, it asks to "find the z-score such that: etc"

>> No.4497355
File: 9 KB, 126x111, 1329637454909.jpg [View same] [iqdb] [saucenao] [google]
4497355

>>4497319
Bumping for help/clues

>> No.4497367

>>4497319
Is z-score a number? My guess for the first two would be to integrate the function from 0 to z and set it equal to the answer it gives and use the quadratic formula to solva for z.

For the last two integrate from z to 2.


Are you even supposed to be integrating in this class? What class is it?

>> No.4497374

>>4497367
>>4497319

Try <div class="math">\sqrt{2} - 2</div> for the first one and see if that answer is right.

>> No.4497379

>>4497374
*<div class="math">2-\sqrt{2}</div>

>> No.4497385

>>4497374
>>4497367
seems to be wrong. And it's a probability and statistics course. And i dont think the z-score formula is how you do it. Not sure.

>> No.4497396

>>4497385
How many tries do you get? I mixed up the order of the numbers. Try the <div class="math">2-sqrt{2}</div> if you can afford to.

Never heard of z-score, there has to be an example in your book for you to compare it to.

>> No.4497410

>>4497396
I don't own the book and I have unlimited tries. I'll try this one real quick.

>> No.4497416

>>4497396
Yeah, that didn't work either. Thanks for helping out though.

>> No.4497472

bump for help

>> No.4497512

>>4497319
>>4497472

According to the table in the back of my book, (and if i'm reading it right)

a) z=0
b) z=2.11
c) z=-1.07
d) z=-1.55

>> No.4497520

>>4497512
That totally worked. I need to get me one of dem books.
Only incorrect one was c = -1.07
It's suppose to be 1.07.
Thanks man

>> No.4497540

>>4497520
https://statistics.laerd.com/statistical-guides/normal-distribution-calculations.php

https://statistics.laerd.com/statistical-guides/img/normal/normal-table-large.png

>> No.4497552

>>4497520
And i'm fairly certain it should be -1.07, so i assume ...

No wait, it should be 1.07
I'm stupid .

>> No.4497576

A) 1/4
B) 1
C) 0