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/sci/ - Science & Math


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4107746 No.4107746 [Reply] [Original]

Hey /sci/

Given 2 functions <span class="math">f(x)[/spoiler] and <span class="math">g(x)[/spoiler]

I know that <span class="math">\lim_{a\rightarrow b} f(x) = g(x)[/spoiler] but I don't know anything about the limit itself.

Is there a way to calculate the limit itself?

For instance let's say that I know <span class="math">f(x)[/spoiler] and <span class="math">f'(x)[/spoiler].

Given these functions is there a way to calculate the limit itself e.g. <span class="math">\lim_{h\rightarrow 0} \frac{f(x + h) - f(x)}{h} = f'(x)[/spoiler]

>> No.4108267

Anybody?

>> No.4108274

>>4107746
> Lim a->b

But what is a?

>> No.4108283

>I know that \lim_{a\rightarrow b} f(x) = g(x) but I don't know anything about the limit itself.
>\lim_{a\rightarrow b}
>f(x)
>g(x)
>a
>b
>x

the time required to dispel your confusion is more than I am willing to waste

good luck, my plug-n-chug lemming

>> No.4108301

I dont understand the qustion.

Just solve g(x) for your x value and you know the limit itself.

If you want to know the derivative you can just calculate it.

>> No.4108322

I have the two functions but not the limit that makes f(x) into g(x).

>> No.4108323

>>4108322
What the fuck are you talking about?

Your question makes no sense egg for brains.

Post the whole thing again, but actually FUCKING THINK.

>> No.4108342

>>4108323

Okay, let me clearify.

I have two functions f(x) and g(x).

I know that g(x) can be calculated from f (x) by using a limit in the same way that h´(x) can be calculated from <span class="math">\lim_{h\rightarrow 0} \frac{h(x + h) - h(x)}{h}[/spoiler]

But i don't now how to calculate f(x) from g(x).

>> No.4108346
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4108346

>>4108342

>> No.4108355

>>4108342

integrate g(x)

>> No.4108356

do you mean:
<div class="math"> \lim_{a\rightarrow b} f(x,a) = g(x)</div>
because that would make a little more sense.

>> No.4108360

>>4108356

Yeah.

>> No.4108374

>>4108360
well, f isn't going to be unique. for example if
g(x) = x^2
then
f(x,a) = x^2+a-b
or
f(x,a) = (x+a-b)^2
or
f(x,a) = a*x^2/b

do you want any solution?