/sci/ - Science & Math

>>3725494
But OP you already solved it, y=0.

>>3725508
solve for x

ok heres another one since my dick is only 4 inches long erect

y=1/x - (4/x-1) - 1, set y=o and solve the resulting equation

If 11x-30-x is all contained in the square root bracket, then x being 3 would solve the equation.

>>3725522

No solution.

>>3725527
-x isnt within the bracket HAHAH TOO BAD FAGGOT THOT IT WAS THAT EZ HUH WELL I DIDNT SKIP TWO GRADES JUST FOR THIS

WOULD YOU DANCE

IF I ASKED YOU TO DANCE

WOULD YOU RUN

AND NEVER LOOK BACK

WOULD YOU CRY

IF YOU SAW ME CRYING

AND WOULD YOU SAVE MY SOUL TONIGHTTTTTTTTTTTTTTTTTTTTTTTTTTT

happy 9/11

>>3725537
x=sqrt(11x-30)
x^2=11x-30
0=x^2-11x+30
x=11+/-sqrt(121-120)/2
=6,5

>>3725537

Okay, next time write the equation more clearly.

Now that I know:

x is -5.

>>3725552
>>3725558

Shit, meant 5 or 6. Got it before me.

>>3725552

This is interesting:

"x=11+/-sqrt(121-120)/2"

I've never been shown this way to figure out a polynomial factor. I just went

(x - 5)(x - 6) with -5 and -6 being factors of the 30 and -5 and -6 adding to -11.

>>3725572
>>3725552

Oh wait, I see it now. You just used the quadratic formula skipping a few steps. Gotcha.

kk thanks all i got this shit on lockdown

>>3725522
<span class="math">
0 = \frac{1}{x} - \frac{4}{x-1} -1
0 = x + 1 - 4x - x^{2} + x
0 = x^{2} + 2x -1
x = \frac{-2\pm\sqrt{4+4}}{2}
x = -1 \pm \sqrt{2}
[/spoiler]

>>3725522
<span class="math">
0 = \frac{1}{x} - \frac{4}{x-1} -1

0 = x + 1 - 4x - x^{2} + x

0 = x^{2} + 2x -1

x = \frac{-2\pm\sqrt{4+4}}{2}

x = -1 \pm \sqrt{2}
[/spoiler]

y = 0
y = (11x - 30)^(1/2)

0 = (11x - 30)^(1/2)
0 = 11x - 30
30 = 11x
x = ~2.72