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/sci/ - Science & Math


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File: 38 KB, 1920x886, raduis.png [View same] [iqdb] [saucenao] [google]
3055944 No.3055944 [Reply] [Original]

Show the area inside the circle but outside the equilateral triangle as a function of x.

>> No.3055956

>>3055944
Do your own homework.

>> No.3055961

>>3055956
lol engineer detected

>> No.3055965

nah lets help him out.

its 6pix^3 + 6x + 6

>> No.3055972

>>3055965
let me guess your a biology major

>> No.3055993

>>3055972

math/econ major. lol do your own homework. if you really can't do this problem... tell your teacher you need to be placed in a lower level class again.

inb4 you call next person chem major

>> No.3056014

can we assume that the vertical line and the horizontal x form a right angle?

>> No.3056017

>>3055993
lol econ doesn't need math you faggot

lrn2AustrainSchool

BITCH

>> No.3056023

>>3056014
YES AND ASSUME THAT R=RADIUS OF THE CIRCLE

>> No.3056037

>>3056017

econ doesnt need math? what? im just taking it because i like both subjects.

austrain school is no fun.

>> No.3056064

haha okay how about if you show us how far you got i'll help

>> No.3056081

lol I solve it. Here is value if you don't believe me.

at x=4 the area is 9.827

>> No.3056102

you didnt solve it >_> you just gave me a value of x and the outcome using a function. what function are you using and if you knew the function why bother asking. this is a simple highschool problem

>> No.3056123

pi*r^2-.5*x*sin(60)

>> No.3056133

thats not final equation. you still have the r variable in there.

>> No.3056144

>>3056102
cause cocky faggots like you can't solve it

>>3056123

has to be solved algebraically

>> No.3056212

>>3056144

butthurt OP cant use law of cos when he just applied law of sin

>> No.3056241
File: 75 KB, 604x453, pi_xsquared__dividedby3_minus_xsquared_sin60_dividedby_2.png [View same] [iqdb] [saucenao] [google]
3056241

theres a clue in the picture lol im getting bored of playing around with this post.

>> No.3056244
File: 62 KB, 480x600, son_i_am_disappoint.gif [View same] [iqdb] [saucenao] [google]
3056244

>>3056212
law of consines on an algebraic problem?

>> No.3056281

>>3056241
lol still using trig. why do engies fail so much

>> No.3056287

>>3056244
still algebra. gtfo OP

>> No.3056295

>>3056244
>law of consines on an algebraic problem?

looks like a spelling problem to me

>> No.3056309
File: 104 KB, 500x346, He_Mad.jpg [View same] [iqdb] [saucenao] [google]
3056309

>>3056287
lol u mad

>> No.3056302

>>3056281
op posted 2nd part in trig :P no need to edit it. plus how would you find r without trig faggot.

if you cant figure out (x^2(sqrt3))/4 then you really shouldn't be here still. i gave you your answer so gtfo.

>> No.3056353

you faggots are retarded

r=x/sqrt(3)

x^2(pi/3-sqr(3)/4) is the correct formula. No trig functions needed.

>> No.3056370

pi*r^2-(3rxsin(30))/2

r=x/(2*sin30)

>> No.3056385

>>3056370
lol x=r? Chemist detected

>> No.3056386

i da gay

>> No.3056392

>>3056386
engineer detected

>> No.3056405

>>3056385
psychologist detected

>> No.3056414

>>3056405
he mad lol

>> No.3056443

guys i need help with this please

>> No.3056556

>>3056443
we solved it already :P

>> No.3056578

lol morans

>> No.3056596

>>3056556
>>3056578
>>3056443

they mad

>> No.3056598

>>3056578
morans

>> No.3056610

>>3056596
no u

>> No.3056620

>>3056610
HE MAD

>> No.3056626 [DELETED] 

I came up with

<span class="math"> \displaystyle{ f(x)=\frac{x^2}{12} (4 \pi - 3 \sqrt{3} ) } [/spoiler]

:/

>> No.3056650

>>3056620
no

>> No.3056660

>>3056626
thats right >_>

>> No.3056676

<span class="math"> \displaystyle{ f(x) = x^2 \left( \frac{ \pi}{3} - \frac{\sqrt{3}}{4} \right) } [/spoiler] 

>> No.3056710

>>3056676
You fucking faggot copying my answer and putting it in jsmath form

>>3056353

>> No.3056725

>>3056710
wut :|

>> No.3056780

2*pi*((x^2)/2.99)-(0.33^2)