/sci/ - Science & Math

What mountain is that
i want to spend the rest of my life on that awesome mountain

Notch resides here

>>2953800
this

Check amount of digits, divide by power of 10 that has same amount of digits and truncate to get one of the digits.

>>2953817
>>2953800

Not OP, but that looks like a mesa, not a mountain. Probably one of the ones in the Andes that inspired the Professor Challenger 'Lost World' stories.

>>2953788
What the fuck am I reading?

>>2953833
Oh, title said PHP.
Well then, here's a pseudocode conversion of the Mathematica code above.

1. Create an array of the integer digits of your number
2. Multiply the array values
3. Check if you've gotten a new number
3.1 If new number, put it on a stack (i.e. an array in PHP) and repeat from 1 with your new number
3.2 else break

i don't know php, but you can do this pretty easily using the rounding functions of excel

>>2953876

and do every step by step!!!?? I want it automatic!!

>>2953928
Well then code it, it's less than ten lines

>>2953928
wat

>>2953788

def nomnom(number)
number_array = number.to_s.scan(/./)
output = 1
number_array.each {|n| output = n.to_i*output}
return output
end

a = nomnom(356)
p a
p nomnom(a)


Dunno how to do it in your moon language though.

>php

fuck dat shit

vector<int> *dodatshit(int n) {

vector<int> *t=new vector<int>;

do
{
t->push_back(1);

do
{
t->back() *= (n - 10*(n/10));
n /= 10;
} while (n > 0);

} while ((n=t->back()) > 9);

return t;
}

>php

fuck that shit

vector<int> *dodatshit(int n) {

vector<int> *t=new vector<int>;

do {
t->push_back(1);

do {
t->back() *= (n - 10*(n/10));
} while ((n /= 10) > 0);

} while ((n=t->back()) > 9);

return t;
}