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/sci/ - Science & Math


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2747919 No.2747919 [Reply] [Original]

This will seem really easy to many of you but don't troll too much. I'm self-teaching AS Level Maths and I got stuck on this question.

Pic related.

Anyone mind explaining how to get the answer. Got a feeling you start by multiplying top and bottom by denominator, cleaning up then cancelling a bit more.

Halp.

>> No.2747924

>>2747919
>Got a feeling you start by multiplying top and bottom by denominator, cleaning up then cancelling a bit more.
That's exactly what you should be doing. You already have the right idea, so you shouldn't be having any problems.

>> No.2747931

>>2747924
Actually, thinking about it for a second, you don't even need to do that. Just remember that <span class="math">\sqrt{x} = x^{0.5}[/spoiler].

>> No.2747932

laws of indices.

>> No.2747939

>>2747924
>>2747931

Thanks, will just try playing with it a bit more and see what I get. I usually get close but mess up. Probably due to what you just said to remember.

>> No.2747949

you can split that equation into x/x^(1/2) + 5x^3/x^(1/2)

At this point simplification is easy.

>> No.2747958

(x+5x^3)/(sqrt(x))
=(x+5x^3)x^-1/2
x^.5+5x^2.5

>> No.2747959

>>2747931

Got x^1/2 + 5x^5/2 which seems right. Thanks for the help.

>> No.2747963

>>2747949

That would work due to common denominator right which keeps it equal?

>> No.2747975

<span class="math">\displaystyle\frac{x+5x^3}{\sqrt{x}} = \displaystyle\frac{x+5x^3}{\sqrt{x}} \cdot \displaystyle\frac{\sqrt{x}}{\sqrt{x}} = \displaystyle\frac{x\sqrt{x}+5x^3\sqrt{x}}{x} = \displaystyle\frac{x\sqrt{x}}{x}+\displaystyle\frac{5x^3\sqrt{x}}{x} = \sqrt{x} + 5x^2\sqrt{x} = x^{0.5}+5x^{2.5}[/spoiler]

>> No.2748001

how old are you?

>> No.2748014

>>2748001

18. I dropped out so didn't do this when I was meant to. Decided I love Maths so going back to college to get my Maths A level so I can look at University prospects.

>> No.2748027

>>2748014

if you are going back to year 12 then they will teach this shit at college. dont worry too much about it

>> No.2748038

>>2748027

Getting a (massive) head start so I can get an A* for Cambridge. Should be able to pull of As in Physics and Computing as they come naturally.

>> No.2748061

>>2747963
correct

>> No.2748069

Instead of starting my own retarded thread, let me pop this one in here:

t=(s+r)/(s-r)

What is s?

I know it's a retarded and easy question but I've been tried it multiple ways and sucked. Christ, how hard is it teach oneself basic math?

>> No.2748084

>>2748069
<span class="math"> s = \frac{r(t+1)}{t-1} [/spoiler]

>> No.2748086

>>2748038
If you can't do the original question on your own without help you won't get into Cambridge, regardless of an A* or not. STEP will fuck you in the anus, as will the whole course. There's a big difference between Cambridge math and maths at other universities.

>> No.2748099

>>2748084
Just giving me the answer isn't exactly helping me, I would rather like a hint or instruction.

>> No.2748114

>>2748099
Different guy here;

t=(s+r)/(s-r)
t(s-r) = s + r
ts - tr = s + r
ts - s = tr + r
s(t-1) = r(t+1)
s = (r(t+1))/(t-1)

>> No.2748124

>>2748086
Nothing wrong with having aspirations. I had the right idea in the first place anyway, just the poor school I attended, nor the CGP book I had taught me the rule someone else did in this thread which allowed me to solve it in one step.

>> No.2748126

>>2748114
Fuck, I knew it was something like that but never got it. Oh well, thank you anon.

>> No.2748144

>>2748099
<span class="math"> t=\frac{s+r}{s-r} [/spoiler]
<span class="math"> t(s-r) = s+ r [/spoiler]
<span class="math"> ts - tr = s + r [/spoiler]
<span class="math"> ts - s = r + tr [/spoiler]
<span class="math"> s(t-1) = r(1+t) [/spoiler]
<span class="math"> s = \frac{r(1+t)}{t-1} [/spoiler]

>> No.2748153
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2748153

>>2748099


hey man sure we like to help you with this shit but i doubt you will get into cambridge. not trying to put you off though. but yea forget cambridge and computing is going to be hard.

i know a guy who got an offer from Imperial of A*A*A in maths physics and chemistry and he couldnt get into cambridge. also hes on a B for computing

>> No.2748155
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2748155

>>2748144
FFFFUUUU!!

>> No.2748159
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2748159

>>2748144
>>2748155

meh, double doubles for me
:D

>> No.2748184

>>2748159
<span class="math">\displaystyle\sum_{whore}^{attention}[/spoiler]

>> No.2748221

>>2748184
<span class="math">\displaystyle\sum_{cunt}^{lick}her[/spoiler]

>> No.2748231

>>2748221
>Implying he has one

>> No.2748256

>>2748231
<span class="math">\displaystyle\int_{everywhere}^{implying}implications[/spoiler]

>> No.2748287

<span class="math"> \displaystyle\sum_{reading}^{whatthefuck}ami [/spoiler]

>> No.2748313 [DELETED] 

>>2748287
\displaystyle\prod_{lolz}^{i}dunno

>> No.2748318

>>2748287
<span class="math">\displaystyle\prod_{lolz}^{i}dunno[/spoiler]

>> No.2748362

>>2748184
>>2748221
>>2748256
>>2748287
>>2748318

<span class="math"> \int_{\mathbf{mfw}}^{\textbf{u guys}}\textbf{cannot into math} [/spoiler]

>> No.2748368

<div class="math">\mathbb{F}_{\mathrm{ags}}</div>

>> No.2748395
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2748395

>>2748362
"\int_{\mathbf{mfw}}^{\textbf{u guys}}\textbf{cannot into math}"
>u guys
>cannot into
>maths

OMNOMNOM, the irony is delicious!

>> No.2748408

>>2748395

>implying latex coding = math

>> No.2748412

Pretty funny, I actually just helped my 14 year old brother understand this 2 days ago. what a coincidence!

>> No.2748422

>>2748408
>implying implications.

>> No.2748425

>>2748256


>>2748408