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/sci/ - Science & Math


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2599480 No.2599480 [Reply] [Original]

Let's see how smart /sci/ REALLY is

Simple question but not for those who don't understand math.

Is this a function?

f(x) = 0.009x^2 -15 / (not ( X ≥ -5 and X ≤ 5))

>> No.2599488

>>2599480
I hate functions. They make no sense. I'm a number cruncher.

>> No.2599505

>>2599480
moar of OPs girl

>> No.2599517
File: 2 KB, 127x91, boxygtfo.jpg [View same] [iqdb] [saucenao] [google]
2599517

>>2599505
thats fucking boxxy you newfag!

>> No.2599516

>>2599505

>OP's girl
>not boxy

please leave

>> No.2599523
File: 3 KB, 126x108, sci5.jpg [View same] [iqdb] [saucenao] [google]
2599523

>>2599516
awwwwww yeeeaaaaaahhhh!!!

>> No.2599524

>>2599480
>implying any of these idiots on /sci/ truly know what a function entails

>> No.2599526

Do your own homework faggot

>> No.2599548

>>2599526
confirmed for not knowing

>> No.2599561

I think it is. Just not a continuous one

>> No.2599583

>>2599517
>>2599516
No. That's boxxifiedrandomgirl

>> No.2599612

no it is not a function correct me if I am wrong

>> No.2599631

>>2599612
correction: you're are wrong.

>> No.2599632

>>2599517

Fuck off EK.

Show me your tits.

>> No.2599647

>>2599631
What's your reasoning?

>> No.2599649

hail the queen

>> No.2599651

>>2599647
*you're

and because i can tell from the OP, and from seeing quite a few functions in my time.

>> No.2599655

>>2599632
>fuck off EK
>show me you're tits

pick one.

>> No.2599656

f(x) means that it is a function of x (responding = y) whether or not there are any values that work is irrelevant

>> No.2599660

>>2599656
>he thinks a function is any relation
>laughing whores

>> No.2599664

EK, the fat british dumb cunt who suffers from Aspergers Syndrome.
I am so unfortunate that I lurk /sci/ the same time of the day you do, and have no other hour to do so.

>> No.2599671
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2599671

>>2599655
>>2599651
>>2599631
>>2599523
>>2599517

>> No.2599673

I would also like to see reasoning and its you're not you're are

>> No.2599677

>>2599660
Do explain. If you can that is.

>> No.2599688

>>2599677
here's a simple enough definition for you:

a relation in which each element of the domain is paired with exactly one element in the range

>> No.2599692
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2599692

>>2599673

>> No.2599694

>Everyone thinks this is a schoolwork thread
>no one has any idea except pulling out guesses from their ass

>> No.2599707

yes it is, for each x there is only one f(x)

>> No.2599708

>>2599688
But a function is a relation

>> No.2599716

f(x) = 0.009x^2 -15 / (not ( X ≥ -5 and X ≤ 5))

for any value of x except 5, ( X ≥ -5 and X ≤ 5) returns 0
f(x) = 0.009x^2 -15 / (not 0)
for well you know, "not 0" is 1
f(x) = 0.009x^2 -15

for x=5, ( X ≥ -5 and X ≤ 5) returns 1
f(x) = 0.009x^2 -15 / (not 1)
for well you know, "not 1" is 0
f(x) = 0.009x^2 -15 / 0
ERR: DIVISION BY ZERO

so, the function can be easily defined for R-{5}

>> No.2599714

>>2599694
...okay i was trolling up until now, but seriously....

http://en.wikipedia.org/w/index.php?title=F%28x%29&redirect=no

>> No.2599713

>>2599708
indeed. Where only 1 x is paired with 1 y.

>> No.2599718

>>2599716
THIS NIGGA KNOWS WHAT HE'S TALKING ABOUT!

So is it a function or not?

>> No.2599734

>>2599718
>so, the function can be easily defined for R-{5}

>> No.2599785

That's very cool. I'm not math heavy at all, so I've never seen straight logic thrown into math (by that I mean basic logical operators like ~(x>-5 ^ x<5).

>> No.2599869

>>2599655

Both. Do the math.

>> No.2599915
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2599915

>>2599785
>yfw even the most basic graphing calculators have logic notation and operations now

>> No.2599923

>>2599713
An x value can have no y value and still be a function of x. It just can't have the same y value twice.

>> No.2600077

>>2599915

I ain't never seen that shit.

>> No.2600217

>>2600077
My calc has a whole logic button bro

>> No.2600490

What's the difference between a function and an equation.

Herp derp.