/sci/ - Science & Math

sure is homework in here.

it is homework and its also one that i cant solve :D

there are 3 variables on hand and both tensions is also unknown which makes for 5 unknown variables. ive gotten 121 = 30z - 20x- 4y with x being the horizontal component and z being the length of one of the wires by using pytaghoras theorem and eliminating a pair of equations but that seems about it

ive also tried to analyze the system horizontally and vertically, but there are too many unknown variables rendering it useless

>>2552287
I only do the hw of cute chicks who offer me Bj's.

Unless you want to set up an appointment, you are on your own.

>>2552287
>>2552364
Ok, post some big tit pics or somthing cool and I will help you

yea well at least i didnt lie and say it wasnt homework unlike most people ( this isnt homework, i just forgot how to do it, etc) anways any hints would be appreciated

>>2552376

cool

Answer is 4.32m.

hey op, is this highschool or first year college?

>>2552390
hintssss

>>2552392
first year college, why?

>>2552396

Sorry I forgot the spoiler tags on your homework.

can give hints on the process of acquiring the answer?

assuming this system is in equilibrium, you arent working with any x-component of force

>>2552417

Only if you give a citation to this thread when you present it to the teacher.

this is a bitch of a question OP. not going to do it. but here is some hints

- there's 7 unknowns, the 2 tensions, 2 reaction forces at both B and C, and y
- you can get 6 equations from statics analysis, 2 at each point A, B, C
- the seventh equation you need to find from the geometry.
- solve

cunt of a question really. it'll take a while to work through. goddamn i don't miss this shit

In equilibrium so tension on left hand side equal to tension on right, right?

>>2552420

meaning the resultant of x component is zero right?
so:
sin (angle1) x Tension 1 - sin (angle2)X Tension 2 = 0

>>2552421
he probably doesnt even understand English

>>2552384
That pic was ok, I guess I will throw you a bone...

The tensions are the same in a pulley

>>2552332
>>2552440
>>2552427

There are not two tensions! There is only one Tension! It is a fucking pulley!

>>2552440

correct. i'm working on this problem and it is quite the bitch. may give up

>>2552446
>>2552446
>implying this is a pulley

lolno

>>2552453
>>2552453
>doesn't know what a pulley is

this is a concentrated load on a cable, with 2 supports, not a pulley.

>>2552427
>>2552427
>this is correct

>>2552453
it's only a pulley if the bucket is on a roller. although it kinda looks like it is. but OP never said anything about it so i guess it;s not.

and OP if it says it in the question and you didn;t write it here you are a FUCKING DINGO

(yes, dingo)

>>2552474

no it did not say on the problem :)

>>2552427
>>2552440
>>2552455
>>2552287

Take u as the base of the left triangle, z as the hypotenuse.

Tensions are the same.
Then X force equation
=> Cos 01 + Cos 02 = 0
=> u/15 + (10-u)/(15-z) = 0

p theorem on the left triangle
=> u^2 + (y-2)^2 = z^2
on the right triangle
=> (10-u)^2 + y^2 = (15-z)^2

I get three equations, three unknowns (one actually has two unknowns). This systems is easily solved.

\thread

http://books.google.com/books?id=JFuUEoT0iIUC&printsec=frontcover&dq=engineering+mechanics+s
tatics+hibbeler&hl=en&ei=QFJdTavAIsSlcJGVpY4K&sa=X&oi=book_result&ct=result&
resnum=1&ved=0CCYQ6AEwAA#v=onepage&q=cable%20subjected%20to%20concentrated%20loads&f=fal
se


click page 365, read it.

you're welcome

>>2552287
>>2552462
>>2552474
>>2552465


An object is hanging on a wire?
This is a pulley!

yALL TALK LIKE FAGS!
ya an engineer?

>>2552287
ITT

>>2552287

>>2552497
>>2552497
just stop, just stop. i read the first line then didn't read the rest.

>=> Cos 01 + Cos 02 = 0
>=> u/15 + (10-u)/(15-z) = 0
>u/15
>15

>implying 15 is the hypotenuse of the left triangle

kids these days

okay its 01.00 am and im going to sleep, class starts at 7. thanks everyone who helped :D, a really big thanks, sorry i cant help much

>>2552497
>>2552521
Your right, it should have been z...I eplicitly stated it anyway. OOPS. it should be u/z

>>2552427
>>2552440
>>2552455
>>2552287

Take u as the base of the left triangle, z as the hypotenuse.

Tensions are the same.
Then X force equation
=> Cos 01 + Cos 02 = 0
=> u/z + (10-u)/(15-z) = 0

p theorem on the left triangle
=> u^2 + (y-2)^2 = z^2
on the right triangle
=> (10-u)^2 + y^2 = (15-z)^2

I get three equations, three unknowns (one actually has two unknowns). This systems is easily solved.

>>2552521
typo fixed

\thread

>>2552497
=> Cos 01 + Cos 02 = 0

what's 01 and 02?

>>2552537
>Tensions are the same.

nope.jpg

simle geomerty.

>>2552726

yeah i got the same as this. did it slightly differently but merh, nice one.