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/sci/ - Science & Math


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File: 9 KB, 350x350, right triangle.jpg [View same] [iqdb] [saucenao] [google]
2537494 No.2537494 [Reply] [Original]

Hey /sci/ ,
is it possible to find the area of a right triangle with only the hypotenuse?
I went to a math competition, and I just went wat at this problem where you had to do so.

>> No.2537505

>>2537503
This, just set the value to 1

>> No.2537503

>>2537494
you can if its a right angle triangle where the two other sides are the same length

>> No.2537508

>>2537494
>is it possible to find the area of a right triangle with only the hypotenuse?

Yes, it is.

There are 2 pieces of information in your question. See them both.

>> No.2537521

>>2537494
relly? what grade are you in?

>> No.2537522

>>2537494
You know all of the angle measurements and a side length.

You damn well better be able to find the area. How the fuck did you get to a math competition and not know this?

>> No.2537532

>>2537522
how do you know all the angle measurements?

>> No.2537536

>>2537532
we are assuming it is isosceles based on that picture

>> No.2537540

>>2537536
why would you assume that? Are you an engineer or in the 6th grade??

>> No.2537541

>>2537540
because the only specification given is the picture
also, engineer

>> No.2537543

No, it's not.

>> No.2537549
File: 16 KB, 337x375, triangle.jpg [View same] [iqdb] [saucenao] [google]
2537549

derp

>> No.2537547

Yes you can. Let the sides be <span class="math">a, b[/spoiler] so that you know <span class="math">c^2 = a^2 + b^2[/spoiler]. You want to consider

<span class="math">(a+b)^2 =a^2 + b^2 + 2ab[/spoiler]

so that the area is
<span class="math"> \frac{1}{2}ab = \frac{1}{4}( (a+b)^2 - c^2)[/spoiler]

Now I challenge you to determine how to get <span class="math">(a+b)^2[/spoiler] from <span class="math">c[/spoiler]. Here's a hint -- look at the geometric proof for pythagorean theorem.

>> No.2537546

>>2537522
I used to compete in maths competitions, and the simplicity of this would have stumped me.

Although I was 11.

>> No.2537562
File: 25 KB, 314x450, blond-girl-laughing.jpg [View same] [iqdb] [saucenao] [google]
2537562

>>2537541
> engineer

That explains alot. GTFO FAGGOT!

>> No.2537572

>>2537541
lol. this reminds me of one of my calc students who found the area under a curve by taking out his ruler and doing essentially riemann sums, but got it wrong because the graph was just an illustration and not drawn to scale.

he complained because we didn't write "not drawn to scale" in the exam. what a faggot

>> No.2537575
File: 67 KB, 900x600, 1295913511746.jpg [View same] [iqdb] [saucenao] [google]
2537575

>>2537494
Nope. Take a ruler, call the lenght of it your hypothenuse. Incline it at any angle. Construct a triangle.

You can produce an infinite amout of right trangles with different areas, all with the same hypothenus. Hence the hypotenuse alone is not enough to specifcy the area of a traingle.

\thread

>> No.2537577

>>2537547


herping while you derp?

>> No.2537582

>>2537572
therefore >>2537494 this triangle has no right angle?

>> No.2537586

>>2537582
It might, but it doesn't have to. That's just a picture and there are no quantities specified, also the angle is not marked as a right angle.

>> No.2537597
File: 15 KB, 591x313, Untitled.jpg [View same] [iqdb] [saucenao] [google]
2537597

>>2537575
Nope

Two right triangles, same hypotenus, different areas.

\thread

>> No.2537617

>>2537597
You agreed with his post.
Why did you start your's with 'Nope'?

>> No.2537622

>>2537582
we were told it's a right triangle.

>> No.2537623

never new /sci/ was so easily trolled

>> No.2537640
File: 86 KB, 400x400, 1275908326178..jpg [View same] [iqdb] [saucenao] [google]
2537640

>>2537623

>> No.2537645
File: 31 KB, 363x310, 1268777395368.jpg [View same] [iqdb] [saucenao] [google]
2537645

>>2537623
Are you new to 4chan?
Do you know what trolling means?