/sci/ - Science & Math

probability of getting a number is 1, probability of getting that same number is 1/6, probability of getting that same number again is 1/6, multiply them all together and you get 1/36

>>2072989
Wrong. 1/6 * 1/6 * 1/6

1/6*1/6*1/6=1/216

Cool triples thread, but check out my doubles

>>2072995
>I am a massive faggot that does not understand probability.

The answer is 1/36. The first one has probability 1 of being the same as the first one. The second and third have 1/6 probability each of being the same as the first one. 1*1/6*1/6

>>2072995
>>2072996

>>2072995
but there are 6 possible triple outcomes, so its 1/6*1/6*1/6*6

checkem

>>2072996
>>2072995
then what is the probability of getting 1 3 times in a row is 1/216, probability of getting 2 3 times in a row is 1/216....probability of getting 6 3 times in a row is 1/216, add them all up and you get 1/36. the question is asking any triple, not just a specific one

>>2073016
I'm mistaken. You're right.

lmao fags, who said they were 6 sided dice.

PLAYING D&D UP IN THIS BITCH

Also, CHECK EM

>>2073100

Thread derailed.

>>2073100
Cool dubs, but check out my dubs

>>2073118
No.

1/6 x 1/6 = 1/36
The first dice doesn't matter since you need any doubles. You have one possible number on the second dice times 1 possible number on the third dice with a 100% chance on the first dice, so you ignore it.

1/36

>>2073121
>you need any doubles
Why the fuck did I type that, I meant you need any number.

>>2073124
Why did you type that?

Maybe it had something to do with the influence of:
>>2073006
>>2073018
>>2073023
>>2073100
>>2073118

Just a thought.

Ok so assuming 6 sided dice:
The probability of rolling one chosen number is 1/6,
so getting two of a chosen number is (1/6)^2 or 1/36 which leads to triples, being (1/6)^3 or 1/216
The claim that triples have a probability of 1/36 is saying that either doubles and triples have the same probability, which makes no logical sense, or that rolling a single number that you have chosen is the same as rolling doubles, which is also illogical. But because it is not specified in the problem, You do not have to choose the triplet before hand which alters the probability by a power of one.


Now bringing up that the number of sides is not specified we have now set up a pattern that we can use to find any number of repeated rolls on a die that has a positive integer greater than one
sides

If we let S be the number of sides and N be the number of repeated rolls you get the formula
(1/S)^N which is equal to 1/(S^N) or S^(-N)

for a the odds of a triple you have not chosen, substitute (N-1) for N

To test this you can calculate the probability of rolling 13 13's on a 13 sided die which is 3.30169096 × 10^(-15)

D&D vanquished

6/(6^3) = 1/6^2 =1/36=~2.8%

desired outcome divided by total outcomes :: 6 possible triples divided by the total of 216 (6^3) possible outcomes of arrangement of dice.

If somebody has some more general rule about probability that is more broadly applicable I'd like to know them since I'm not formally educated about this stuff.

It's (1/6) * (1/6) * (1/6) faggots.

Learn some probability.

let me enlighten you guys, in a way thats very simple to understand.

getting triples is 1/36. why? because you are not guessing the first number. the first number can be anything, so its probably is 1 out of 1. then, you know the rest. (1/1 * 1/6 * 1/6=1/36)


if you are trying to GUESS the first number BEFORE you roll, and get triples, then yes it is 1/216.

Wow, you guys are fucking geniuses. Way to go writing on and on about little kids understand.

There are 216 ways to roll three six-sided dice. There are six ways to roll triples with those dice. 6/216 = 1/36.

Bonus round: If someone rolls three dice and they say that they rolled at least one five, what are the odds that they rolled triples?

6 success

{ (1,1,1) .... (6,6,6) }

216 possiblities.

{ (1,1,1), (1,1,2), ... (6,6,6) }


P(X=(x,x,x))= 1/36

>>2073707
One way to get triples with 5's, and 216 - 125 = 91 ways to get a 5, so <span class="math">\frac{1}{91}[/spoiler].

>>2073723

where did that fucking 125 come from? 5*5*5?

wow. im impressed with your stupidity

>>2073707

1/36, nigger

>>2073737
Oh look, the fucktard from that other thread.

I'm not even going to honor you for an explanation. But if you don't believe me, note that 6*6 + 6*5 + 5*5 = 91 (another way of getting that value).

>>2073707

see my explanation

>>2073685

>>2073759
He's saying the same thing as you, except not in the retarded way in which a 16 year old would describe it.

>>2073737
He's right.. Learn what your talking about before you speak.

>>2073760
>oh hey look guys math that didnt even solve the problem

>>2073784
This is a major troll, right guys? Sometimes I'm not sure; but with this one, I don't know how anyone could POSSIBLY be that stupid.

>>2073791

guessing someone's rolls is the same probability of achieving those rolls. god damn man, no troll here.

>>2073804
There is one way you get get triples with at least one 5. There are 91 ways you can get at least one 5. What could you POSSIBLY not understand about that?

>>2073809
because that wasn't the question.
the question was pretty much saying "there are two dice that you don't know what their values are. what is the probability that they are both 5?"

> this thread

ohboyherewego.jpg
order vs no order

MOAR IMPORTANT QUESTION:

what is the probability that a random post ends in dobles

also, check out mein dopple

>>2073907
fail,

>>2073824
No, thats not what the question asked at all, since you don't know WHICH die came up 5, or if multiple came up 5.

Think about it this way - there is a greater proportion of non-triples that include 5 than there are triples that include 5. Only 1/6 of triples include 5, while 91/210 non-triples include 5. So if you have a roll that includes five, you are excluding many more non-triples than you are excluding triples, so the probability shifts in favor of not getting triples.

Think about it from this perspective: what if you roll three six-sided dice and none of them come up as 5? Then, its exactly the same as if you rolled five-sided dice instead, so the odds of getting triples is 1/25. If the test ("did you roll at least one five") makes the probability of something go down if the test turns out negative, then the test ALSO has to make the probability of that thing go up if it turns out positive. This is because asking "did you roll a five" doesn't change the probability of them rolling triples - it only helps you determine whether or not they rolled triples.

Remember, probabilities are statements about knowledge.

you're with monty hall. he tells you theres a car behind one of three doors. you pick a door.
he opens one of the other two doors and shows there is nothing behind it, and asks you if you would like to switch doors.
you switch doors, remembering your HS conditional probability. to your horror he opens your door and nothing is behind.
you go home and all your friends and family give you tons of shit about how it was equal chance, and you should have stuck with what you first chose.

what is the probability you an hero?

>>2073923
I like you. You're intelligent, but not a dick like I am.

>>2073923
your shits retarded, because your 91 combinations include shit like 3,2 AND 2,3.

1/36

>>2073707
1/36

>>2073948
He's not the one who posted 91; that was me. And it's correct, you fucking samefag; you WANT to consider all 216 permutations. If you viewed combinations as probabilistically equivalent to permutations, you would be implying that the odds of rolling three 6s are equal to the odds of rolling one 6.

just to clear things up...
The guy who answered 1/91 was responding to A DIFFERENT QUESTION than the OP.
and he already explained that the answer to the OP's question is 1/36...
and he is right on both counts.

Ok? no more confusion?

>>2073985
Yeah, I guess I should have made that clear. But I think we can send this thread to its grave now.

1/91 is the correct answer.

6/216

The probability for each number is 1/6 and the probability to get it three times in a row is (1/6)^3=1/216

>>2074175
I like you.

The probability that my post will end in doubles is 1%, right?

>>2074180
End in doubles?