/sci/ - Science & Math

Let me WolframAlpha that for you.

http://www.wolframalpha.com/input/?i=x^2-2kx%2B1%3D0

See: "Solutions for the variable x"

√(b^2 - 4ac) > 0

where a = 1, b = -2k and c = 1

>exuation
Fucking spelling, how does that work?

>>1862897

minus the wq. root. my bad

just b^2 - 4ac > 0

▲=b^2-4ac
=(=2kx)-4(1)(1)
4kx^2-4
4kx^2-4=0
-4(kx^2+1)=0
k=0 or k+1=0
k=0 or k=-1

guize is this right?
>>1862928>>1862928>>1862928

bump for homework

anyone?

You want (2k)^2 - 4 > 0
Which implies k^2 > 1
So k < -1 or k > 1

>>1862928
that gives one real root, plus why the hell do you have x in your discriminant?

∆ = (2k)^2 - 4 > 0
4k^2 - 4 > 0
(k-1)(k+1) > 0

k > 1 or k < -1

> 0
how the hell did you get this thingy?

...

fuck this, im going to bed!