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/sci/ - Science & Math


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1847543 No.1847543 [Reply] [Original]

i'm trying to teach myself some calculus and i have a question. does a function f(x) exist who's derivative is equal to the exp of itself? how would you work out what f(x) is?
thanks!

>> No.1847554

Sorry I can't help you. I'm bad with math. 2N+2N looks 4N to me.

>> No.1847562

You mean dy/dx = e^y? Uhm... You could always separate variables
e^-y dy = 1 dx
Integrate both sides
-e^-y = x + C
e^-y = D - x
-y = ln(D-x)
y = -ln(D-x)

Checking we have
dy/dx = 1/(D-x)
but e^-ln(D-x) = 1/e^ln(D-x) = 1/(D-x)

The answer is yes, y = f(x) = 1/(D-x) works for every real constant D.

>> No.1847571

Maybe I'm understanding it wrong, but <span class="math">\int x^x dx[/spoiler] is not defined.

>> No.1847578

>>1847571
It's perfectly well-defined, although there may not be an elementary expression matching that function.

>> No.1847581

>>1847562
Derp, that should be
>y = f(x) = -ln(D-x) works for every real constant D

>>1847571
x^x is continuous, therefore, it is integrable. It probably can't be expressed in terms of elementary functions, though.

>> No.1847584

>>1847578
>>1847581
That's what I meant, thanks for clearing it up.

>> No.1847594

>>1847562
i'm trying to understand, all i don't get is what you mean by separate the variables and how you got from
dy/dx = e^y
to
e^-y dy = 1 dx

>> No.1847602

>>1847594
<div class="math"> \frac{dy}{dx} = e^y</div>
<div class="math"> e^{-y} \frac{dy}{dx} = 1</div>
<div class="math"> e^{-y} dy = dx</div>

>> No.1847606

>>1847594
Multiply both sides by e^-y dx.

>> No.1847615

>>1847606
>>1847602
ok yeah that was a stupid question haha. thank you so much!

>> No.1847648

>He thinks he can learn mathematics outside of a university!

>Aaahahahahahahahaha

>Laughing_attractive_university_students.jpg

>> No.1847652
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1847652

>>1847606 Multiply both sides by dx

>> No.1847664

There are only 1 kinds of people!?

fuck that shit

>> No.1847666
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1847666

>>1847652
Problem, officer?

>> No.1847673

>>1847666
1-forms are legit.

>> No.1847732

>>1847652
>implying you're not a physicist

>> No.1847736

>>1847732
Multiplying with differentials is like dividing by vectors. My physicist opinion.

>> No.1847739
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1847739

>>1847736

>> No.1847745

>>1847736

wtf am I doing with the differential when I'm multiplying with it?

>> No.1847748

>>1847745
You're multiplying with it, obviously!

>> No.1847755

>>1847745
<div class="math">dx = 1 dx = e^{-y}\frac{dy}{dx}dx = e^{-y}\frac{\partial y}{\partial x}dx = e^{-y}dy</div>
Something like that.

>> No.1847763

For one-variable continuous functions you can deal with differentials as if they were normal numbers, i guess