/sci/ - Science & Math

More importantly, whywouldyoudothat.jpg

>>1822990
bitches don't know about my instrumentation amplifiers

It is supposed to be a filter of some sort, probably a notch. Not sure how to start solving it though, until I figure out how to op amp sex.

>>1822938
Ain't that far yet. I've heard op amp is a bitch though.

put a vacuum tube in the circuit

>>1823017
I am not trying to build it, I am trying to figure out what the tits it does.

>>1822938
If it is a 741, pin 6 to pin 2/3 for the obvious answer...

If you're looking for information on how to turn a Static Source Transfer function into an operating equation, and then design a circuit, there's a textbook I can recommend...

>>1823030
I am looking to find out what kind of filter this OP amp is performing, most likely from finding out the transfer function.

It looks like you could use some help.

Hint 1: Those op-amps are non-inverting with unity gain. They simply repeat the input voltage at the output without drawing current from their input when you apply a load to the output.

Hint 2: Do the circuit analysis in the complex frequency domain. This is a linear filter.

>>1823065
I didn't even notice that this circuit is already labeled with impedances in terms of the laplace "s." Carry on.

>>1823065
>non inverting
>unity gain

so it is just a buffer?

also I am not sure how to solve this with the resistor R1 on the top like that.

Also the input to the first op amp, it is in the middle, should I just assume it should go to the + side? or is there something about the middle that is significant.

I never had to do OP amps in my first electrical networks class, and now I have to do them with inductors and capacitors ;_;

>>1823107
>so it is just a buffer?
Yep. The op-amps in this circuit ideally provide a perfect voltage source that mirror the input voltage.

Use nodal analysis. Label all the nodes and currents in the circuit.
Remember that the op-amp input will not draw any current (ideally.)
Treat the capacitors like resistors in the s-domain. Ohm's law applies because they are linear components. V(s)=I(s)Z(s) where Z(s) is impedence.
Where you reference a point in the middle of components, that's simply a voltage division as you would do with regular resistors.

You should ultimately get a linear system of equations. To solve for the transfer function, manipulate the system of eqns to find Vo(s)/Vin(s)

>>1823107
Let me give you some general assumptions to consider with an OPAMP:
1. No Current flows into the inputs.
2. Gain is infinite
3. Output resistance is 0
4. Input resistance is infinite.

Is this an equivalent circuit?

>>1823157
>2. Gain is infinite
Don't let this confuse you, OP. This is open-loop gain and its an internal property of the op-amp. The closed-loop gain is something entirely different and in this circuit it is G=1.

Unless I have calculated wrong, the amplifier in OP's pic has unity gain in the high-pass case only when <span class="math">R_1 C_1 = R_2 C_2[/spoiler].

Stick yo dick into the equal sign part.
Everything can be solved by sticking your dick into something.
MAKE THAT AMP YO BITCH NIGGA.

>>1823436
open up the amps asshole?

>>1823457
The possibility of feedback would make me leary of pushing too hard in the ass.

Pump it full of cum and that bitch will be bonnified.
No need for extra amps.
Just make sure you haven't jizzed for like 2 weeks and EXPLODE THAT HOLE.

Oh god now im just fapping hard to that circuit system.
Why is this arousing. FUCK.