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peachy !7227PeachY Fri Sep 17 21:43:33 2010 No.1769442 [Reply] [Original]

question of relativity:

say joe is moving through space in a space suit at .5 the speed of light and jim, also moving through space in a space suit at .5 the speed of light. Joe and Jim are both head in opposite directions towards one another, will Joe see Jim and Jim see Joe? Will Joe or Jim be moving at the speed of light relative to one another?

>>	Anonymous Fri Sep 17 21:44:33 2010 No.1769445 http://en.wikipedia.org/wiki/Velocity-addition_formula#Special_theory_of_relativity

>>	Anonymous Fri Sep 17 21:45:33 2010 No.1769446 >>1769442 They will see each other but not moving at c. You will have to use eienstien's velocity addition rule.

>>	peachy !7227PeachY Fri Sep 17 21:46:33 2010 No.1769448 >>1769446 how do i plug data into the equation? (highshool fag here) i want to see if both are traveling at .6 will one be faster than light relative to the other.

>>	Anonymous Fri Sep 17 21:47:33 2010 No.1769449 Opposite directions towards one another?

>>	peachy !7227PeachY Fri Sep 17 21:48:33 2010 No.1769450 >>1769449 ehh i worded it badly but consider the two coming towards and then passing one another

>>	Anonymous Fri Sep 17 21:50:33 2010 No.1769452 >>1769450 Ah ok. I'm not a physicist, but I imagine they are moving at 1c relative. Thats using normal physics though, I think this delves in to relativity and special physics.

>>	peachy !7227PeachY Fri Sep 17 21:50:33 2010 No.1769453 is my math right? .6(c) = 1.8x10^8? c = 299,792,458(.6) = 179875474.8

>>	Anonymous Fri Sep 17 21:53:33 2010 No.1769456 >>1769453 What the fuck are you doing? >>1769445 gives you the right formula

Anonymous Fri Sep 17 21:53:33 2010 No.1769457

>>1769442
http://en.wikipedia.org/wiki/Velocity-addition_formula#Special_theory_of_relativity
Here is the formula
v is the veloctity of one object
u is the velocity of other
c is the speed of light
and s is the actual velocity of them relative to each other

>>	peachy !7227PeachY Fri Sep 17 21:54:33 2010 No.1769462 >>1769457 yes i know where as v= .6(c) u= .6(c) c= lightspeed (meters so s= .6(c)+.6c)/1+(uv/c)

Anonymous Fri Sep 17 21:59:33 2010 No.1769472

so they move at half the speed of light away from each other and the resulting reletive speed is max light speed- i would asume that any light from start of motion would therefore not be able to catch up to either viewer and the result would be each seeing a purpetual image of each other when they were last still- which of course would be traveling towards each viewer at twice their own traveling speed. but any image from each other in motion would not be able to enter the eye unless it was moving forward into it (because you are moving from it at the same speed it would be hovering still, in front of you and would either appear faint or not at all).....i guess

>>	peachy !7227PeachY Fri Sep 17 22:02:33 2010 No.1769483 >>1769472 is that as ever as have gone to be going and where it all begins?

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