/sci/ - Science & Math

(9^n/2 + 0.5) + (9^n/2)

You didn't ask a question. There is no equation or anything in the image. What is the problem?

>>15704566
how does that help i solving that? also may i know how expressions like that are called?

>>15704576
Dont know what its called but then you do the addings and you get
18^(n+0.5)

>>15704580
And because you do the addings the parenthesis shifts to the powers because you cannot really add n and 0.5
So thats the answer

>>15704576
WAIT WAIT WAIT I THINK I GOT IT

9^whatever/2 = √9^whatever

so 3^n+1 + 3^n

3^n x 3 + 3^n = 3^n x 4

>>15704561
[math]9^{\frac{n+1}{2}} + 9^{\frac{n}{2}} = (3^2)^{\frac{n+1}{2}} + (3^2)^{\frac{n}{2}} = 3^{n+1} + 3^{n} = 3^{n}(3 + 1) = 4 \times 3^n [/math]

>>15704588
which is
4.243^n

>>15704645
which means n is about 1,9295
Because
1,9295^4,243
≈
4,243^1,9295

>>15704561
underage b&

>>15704561
The term is exponentiation. Now google it.

>>15704700
I'm op and can say that your answer is incorrect because the question stated that n is a positive whole number

>>15704561
that is literally precalculus algebra, a 10th-11th grade class for 15-17 year olds.

>>15704780
I have parenthesis for the whole thing
I do the first division inside the parenthesis just because
There is no more room to solve for n so the parenthesis shift so that additioning comes last
Which leaves me to their addition because there is no more room to solve for n
Then i find whats 18 to the power of 0.5
Which leads me to an answer to the power of n
And now i can find that n by brute force

I dont really get where i went wrong

>>15704561
what's n? did they tell you?

>>15704969
n is a positive whole number. I managed to find a solution in >>15704591

>>15704561
Nigger have you never learned basic algebra

>>15704618
nice how the only clear and well written answer gets zero replies, almost as if OP was a colossal baiting faggot

>>15704561
Isn't this just [math] 9^{\frac{1}{2}} * 2(9^{\frac{n}{2}}) [/math] ?

>>15704618
Good job anon

>>15704561
for future reference, you use "an" when the next word uses a vowel pronunciation, not simply has a vowel.
in the case of "university", the word is pronounced with a consonant Y sound as the initial syllable, and so it is actually supposed to be "a university".

next time don't be retarded if you want to get into a university

>>15705981
No. (9^1/2)*(9^n/2) + 9^n/2
= (9^n/2)*(9^1/2 + 1) = (9^n/2)*(4)
= (3^n)*4

>>15706509
English is not even my native language

>>15704566
There is a thing called operator precedence. You need to write that in this way:
9^(n/2 + 0.5) + 9^(n/2)

>>15707346
Or you skipped a step like this board usually does

>>15704561
As others have noted, this simplifies to 4*3^n.

But you didn't clarify what the question is. Is it asking us to simplify the expression?

[math] \displaystyle
9^{ \frac{n+1}{2}}+9^{ \frac{n}{2}}= \sqrt{9^{n+1}}+ \sqrt{9^{n}}
=3 \sqrt{9^{n}}+ \sqrt{9^{n}}=4 \sqrt{9^{n}}
[/math]

[eqn] \big(9^{\frac{n+1}{2}}+9^{\frac{n}{2}}\big) = \big(9^{\frac{n}{2}}9^{\frac{1}{2}}+9^{\frac{n}{2}}\big) = 9^{\frac{n}{2}}\big(9^{\frac{1}{2}}+1\big) = 3^n\times4[/eqn]