/sci/ - Science & Math

>>15674924
0*1 = 0
fpbp and /thread

sppp

is that the factorial of zero?

>>15674924
To make calculations corrent when working with binomial coefficients

How many ways can you arrange 0 things?

>>15674945
*correct

>>15674924
n!*(n+1)=(n+1)! <=> n!=(n+1)!/(n+1)
4!=5!/5
3!=4!/4
2!=3!/3
1!=2!/2
0!=1!/1

>>15674924
Because one is a thing and zero is no thing.

>>15674924
because you can arrange nothing only in 1 way

Factorial is just a man-made bullshit operation. 0 could equal 69 if they wanted it to. They set it to 1 for convenience's sake to keep some patterns consistent but it should actually equal 0.

>>15674924
the recursive definition

>>15675031
>he does not know
https://www.youtube.com/watch?v=y-yb_EmVtg0

>>15675053
>more circular logic
Perfect example of what I was saying, thank you based anon

math is retarded. the sooner you learn that, the closer you will be to enlightenment

because we say so

>>15674924
n! involves multiplying n numbers. 0! involves multiplying 0 numbers, so it's the empty product, which is equal to 1 by conventional definition. Why is the empty product equal to 1 and not 0? Probably because if you define it as 0, lots of proofs, especially ones that rely on induction, would have to handle 0 especially, so it's obvious that 1 is actually the natural choice.

>>15674924
x^0 = 1
People just made up this rule because they liked it. Math is not something to be "discovered", some hidden truth about the universe to be amazed about, no math is purely an invention of humans. They create the system, they write the definitions, they draw the symbols, they set the rules. There is nothing to discover in something you yourself invent.

>>15675260
LMAO

>>15675220
>The great Jew at the end of the yellow pill
>Yellow pill: all the secrets without guidance

>>15674924
The only way to pick 0 balls is to not pick any balls.

Because 1 is the multiplicative identity.

>>15675031
>but it should actually equal 0.
Why?

>>15674924
[math] \int_0^\infty x^n e^{-x} dx = n! [/math]
[math] \int_0^\infty x^0 e^{-x} dx = 1 [/math]
That's all there is to it

>>15674924
if 1! = 1 then since n! = n* (n-1)! the plugging in 1 we get 1! = 1 * 0! so 0! = 1! = 1

>>15674924
>Why?

By definition!

>>15674946
Zero?

>>15676817
Not arranging nothing is the only way to arrange nothing.

[math]\dfrac{n!}{n}=\big(n-1\big)!\quad\implies\quad\dfrac{1!}{1}=0![/math]

>>15674924
What why? Zero is different than one, what don't you understand?

>>15676817
Two digit IQ answer.

>>15674946
You can't "arrange 0 things", brainlet.

>>15677091
A reasonable answer, but not a very useful one.

>>15677100
My reasonable answer explains why your question is nonsense.

(n+1)! = (n+1)*n!
1! = 1*0!
1 = 1*0!
0! = 1

>>15677109
Your retarded answer doesn't explain anything, not even your own retarded answer.

>>15675215
nah, your are retarded

>>15676224
indeed

>>15677091
Exactly, because there's no way to arrange it, there's only one arrangement possible for 0 things to be in

>>15675051
This is the real answer.