/sci/ - Science & Math

>>14622509
[math]y=\lfloor 0.25e^{0.28x}-0.1\rfloor[/math]
This produces that sequence but I don't know if it's the expression the faggot who came up with that wants.

>>14622552
Stfu you cum guzzling retarded faggot. Every bad word youll try calling me APPLIES TO YOU NIGGER. YOUR RETARDED INBRED EQUATION IS THE STUPIDEST WAY THIS COULD BE DONE HOLY FUCK WHO THEY FUCK NEEDS DECIIMAL POINT FOR THIS YOU STUPID SHITSKINNED NIGGER DON'T FUCKING DARE REPLY TO THIS THREAD YOU ASS LICKING RETARDED INBRED CHILD OF NIGGERS

>>14622560
Give a better expression then you niggerfaggot.

>>14622563
Before giving you something, I will give your mom my dick. My cum, my seed, shall develop in the very womb that once nourished you. Your brother, Anon 2.0, shall live up to your mom's expectations.
Your mom, my cum-taker, the bearer of children

>>14622552
An actual solution written in TeX gets flamed for actually doing the work.
This place is overrun with children...

>>14622569
I'm sorry that you're retarded enough to get filtered by this anon.

>>14622552
Good solution. Sorry op is retarded

>>14622552
fpbp

Anyways, if op is still conscious. Why not mult-part function?

[0,5]: f =0
(5,6] f = x-5
(6,7) f =1
[7,inf) f= x-6

>>14622509
y=T(x-6)+T(x-7)*(x-7)
Where T is the heaviside theta function

[math]f(x)=-336 + 957.959524 x -1108.68464 x^2 + 698.971296 x^3 -269.302971 x^4 + 66.8979167 x^5 -10.9338310 x^6 + 1.16825397 x^7 -0.0785052910 x^8 + 0.00300925926 x^9 -0.0000501543210 x^{10}[/math]

>>14622621
[math] f(x)=-336 + 957.959524 x -1108.68464 x^2 + 698.971296 x^3 -269.302971 x^4 + 66.8979167 x^5 -10.9338310 x^6 + 1.16825397 x^7 -0.0785052910 x^8 + 0.00300925926 x^9 -0.0000501543210 x^{10} [/math]

>>14622552
Fails on the very next term retard

>>14623158
What do you mean fails?

>>14622589
Because that's lame. In that case, why not just define the function on an element-per-element basis?
>f(1)=0, f(2)=0, etc.

>>14622509
Why.

https://oeis.org/search?q=0%2C0%2C0%2C0%2C0%2C1%2C1%2C2%2C3%2C4%2C5&language=english&go=Search

>>14623177
For x=12 that function yields 7 instead of 6 and gets further divergent from there

>>14622509
>continues for an infinity.
So what are the y values for 12, 13, 14, 20,and 100?

>>14623392
>instead of 6
Where does it say 6??

>>14623392
why would 6 be the next number in the sequence?

>>14622509
Not even worth writing in tex. Also, fuck you because any finite sequence of numbers has infinite functions to describe it.

Y = FLOOR((X(X-1)(X-2)) / (37+13X))

[eqn]\lim_{a \rightarrow \infty } e^{(b-7)^{a}} \div (e^{(b-7)^{a}} + e^{(7-b)^{a}})[/eqn]

>>14623918
Sorry, you have to multiply by b in the beginning.

OP totally destroyed once again

>>14622509
There are infinite solutions.

>>14623158
OP doesn't specify what the 12th therm should be you homosexual.

>>14622552
18 y/o HS student here, please elaborate how you came up with this expression.

test because op is a retard.

>>14622509
Huh. Sure, why not.
1/2*(-5 + x - abs(sgn(-6 + x)))*(1 + sgn(-5 + x - abs(sgn(-6 + x))))
Probably the only valid answer ITT.

Dunno. But clearly from the picture, y converges to x from the right.

>>14622509
>continues for infinity? How exactly?
Y as
11 6
12 7
13 8
14 9
...
Or
12 5
13 5
14 5
15 5
16 6
17 6
18 7
19 8
20 9
...

>>14622509
Here you go:
[eqn]
y =
\begin{cases}
0 &\text{when }1\leq x\leq5\\
1 &\text{when }x = 6\\
x-6 &\text{when }x \geq 7
\end{cases}[/eqn]

>>14629566

>>14623214
because his answer satisfies the request and it's conciser than what you propose

>>14622589
This is the better answer because of continuousness. Nice subtle effort anon
>>14629566
Also acceptable. Participation trophy

>>14623214
Continuous function is better probably. Depends on what question exactly was. I presume they’re always asking for continuity otherwise what’s the point

>>14629566
Kekked and checked.

[math]
f(n) = \binom{n-1}{5} - 5 \binom{n-1}{6} + 16 \binom{n-1}{7} - 41 \binom{n-1}{8} + 91 \binom{n-1}{9} - 182 \binom{n-1}{10}, \quad n = 1,2, \dots
[/math]

>>14623399
>>14623416
It's ok, basic pattern recognition is not for everyone