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12665354 No.12665354 [Reply] [Original]

How would you geometrically represent XOR? An acyclical graph is my best guess.

>> No.12665377
File: 17 KB, 1399x1212, XOR.png [View same] [iqdb] [saucenao] [google]
12665377

Like this.
Easy

>> No.12665589
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12665589

>> No.12665593
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12665593

>>12665589

>> No.12665895
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12665895

>>12665593
1 = [math]+X[/math]
2 = [math]A + B[/math]
3 = [math]A - B + (A*B)[/math]
4 = [math]A + B - (A*B)[/math]

5 = [math]-X[/math]
6 = [math]A - B[/math]
7 = [math]A + B - (A*B)[/math]
8 = [math]A - B + (A*B)[/math]

>>12665593
9 = [math]sqrt(A)-(B^2)[/math]

Given that all squares imply that roots exist, then A must be the root that is discarded from the squaring of B.

>> No.12667241

>>12665354
It depends on what you mean. There are actually several different ways to geometrically represent logical operations.
One way the XOR operation can be represented is by (statements about) orthogonal subspaces of a vector space.

>> No.12667607

>>12665589
This is bullshit.

>>12665354
By marking, that dog can be only in one house in one time segment out of two houses.

>> No.12668260

>>12667607
>bullshit
how exactly?
seems fine for 2-input gates

>> No.12668267

>>12665895
take your meds schizo

>> No.12668279

>>12665354
what one is that? i have to remember. OR is: as long as you have one, you have everything. NOR is: as long as you have one, you have nothing. what is XOR? what's the alternative? this is too spooky to think about.

>> No.12670022

>>12668279
XOR <=> {{0,0=0}{0,1=1}{1,0=1}{1,1=0}}