/sci/ - Science & Math

>>12594397
Q1: 2/3
Q2: 1/9+ 1/3 = 4/9
Q3: 2/5

>>12594397
50%
33%
40%

>>12594422
Wrong

>>12594427
How come?

>>12594406
Correct.

>>12594422
Incorrect.

>>12594406
Explain your answer.

>>12594406
>>12594484
Yes, please

t. Percentage anon

>>12594484
Which one?

>>12594496
Starting from Q1 and so forth..

>>12594495
>>12594484
Well picking each blue ball in the beginning is equally likely, and for 2 of the three balls, the other ball is also blue, hence 2/3.
For second question condition on the first ball picked. If picked from the first box, getting a blue ball is as likely as getting a red ball. If picked from second box (1/3) then only one box contains blue balls so 1/3 that the next ball is blue. Addig up 2/3*1/2 + 1/3 * 1/3 = 4/9

>>12594397
50%
49.5% (33% + 66% / 2)
Roughly 50%, exact value indeterminate(human free will and determination effects the outcome)

>>12594515
>human free will and determination effects the outcome
you are blindfolded and the boxes are shuffled, the pick is random

>>12594515 here, had a brain fart
Question 1 is 33%

>>12594531
Logically, you can pick a blue ball either from box 1 (with 2 blue balls) or box 2 (with 1 blue ball). When you go in for the second one, there is 50/50 chance that it will be here, as it all depends in what box was the "original" blue ball.

>>12594547
Well I certainly had a brainfart, turns out it was in my own correction. This is why they say to always stick woth your first answer.

>>12594547
>there is 50/50 chance that it will be here
nope.
2/3 chance the first blue ball is picked from the first box.
1/3 chance the blue ball is picked from the middle box, in which case you can't pick a second blue ball from that same box.
the only way for another blue ball to be in the same box is to pick the first ball from the first box, which always contains second blue ball.
2/3 * 1/1 = 2/3

>>12594577
The boxes are independant systems dumbass. Box 1 could have 1 million blue balls and it wouldn't change the outcome

>>12594397
Autism check. The boxes were shuffled after the first pick. Sure, the same box might be in the same spot after shuffled with the other boxes, but there is no way of telling if the second draw is coming from the same box while drawing only one ball. This is a vastly different question. There is a reduction in odds by 1/3 of even picking from the same box again. Which crayon color is your favorite flavor?

>>12594584
no, that guy is correct. it's 2/3.

independent systems? are you blind?
THE 3 BOXES ARE ALL PART OF 1 EQUATION

>>12594577
>The boxes are independant systems
Yes
And each box has 1/3 chance of being the one from which you pick a ball

Chances of picking from box 1 = 1/3
Chances of picking from box 2 = 1/3
Chances of picking from box 3 = 1/3

For the first round:
Chances of picking a blue ball from box 1 = 2/2
Chances of picking a blue ball from box 2 = 1/2
Chances of picking a blue ball from box 3 = 0/2

Chances of picking a blue ball = 3/6
Given each box has the same probability of being picked and the fact that they contain the same amount of balls (on the 1st round), each ball has the same probability of being picked.

Chances of picking from box 1 given the ball is blue = 2/3
Chances of picking from box 2 given the ball is blue = 1/3
Chances of picking from box 3 given the ball is blue = 0/3

>Box 1 could have 1 million blue balls and it wouldn't change the outcome
I agree. Of course it doesn't apply for question 3 but we both know that

>>12594397
Q1) 2/3

Q2) 4/9

Q3) 2/5

This reminds me OP, I should post another frog problem thread. Thanks for the inspiration :^)

>>12594406
>>12594756
Pick up