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/sci/ - Science & Math


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11835148 No.11835148 [Reply] [Original]

I've seen this shit posted a few times. What's the problem called, and is the giant fuck off number I can't fit into any calculator that someone always posts an actual solution?

>> No.11835155

[math]
\frac{154476802108746166441951315019919837485664325669565431700026634898253202035277999}{36875131794129999827197811565225474825492979968971970996283137471637224634055579+4373612677928697257861252602371390152816537558161613618621437993378423467772036} \\ + \\
\frac{36875131794129999827197811565225474825492979968971970996283137471637224634055579}{154476802108746166441951315019919837485664325669565431700026634898253202035277999+4373612677928697257861252602371390152816537558161613618621437993378423467772036} \\ + \\
\frac{4373612677928697257861252602371390152816537558161613618621437993378423467772036}
{154476802108746166441951315019919837485664325669565431700026634898253202035277999+36875131794129999827197811565225474825492979968971970996283137471637224634055579} \\ =4
[/math]

>> No.11835158
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11835158

>>11835155
fuck you

>> No.11835164

W|A
solve x/(y+z) + y/(x+z) + z/(x+y) = 4 over the integers

>> No.11835174
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11835174

>>11835158
the horror
the horror

>> No.11835177

>>11835164
>Posts the same thing
>"Just solve it, bro"

>> No.11835187

>>11835177
>doesn't understand WA

>> No.11835190

>>11835148
https://www.quora.com/How-do-you-find-the-positive-integer-solutions-to-frac-x-y+z-+-frac-y-z+x-+-frac-z-x+y-4/answer/Alon-Amit

>> No.11835194

>>11835148
yes, 4 is the actual solution
desu, your calculator sucks

>> No.11835274
File: 87 KB, 993x738, Rätsel.png [View same] [iqdb] [saucenao] [google]
11835274

>>11835148

>> No.11835561
File: 48 KB, 736x563, EFAA95EF-8E2A-4EA2-846C-EE2798E6BB2B.png [View same] [iqdb] [saucenao] [google]
11835561

>> No.11836737

>>11835190
holy fuck, i thought this was just some basic algebra from first glance

>> No.11837656

>>11835274
This one is fukkin easy:
Let pinapple = [math]p[/math],
apple = [math]a[/math]
strawberry = [math]s[/math]
using [math]p = 10[/math] (from equation 1)
[math]
2a + 2s = 10 \\
4s = a \\
2(4s) + 2s = 10 \\
10s = 10 \\
s = 1 \\
a = 4s = 4(1) = 4 \\
[/math]

For the 'hard' part:
Let watermelon = [math]w[/math]
cherries = [math]c[/math]
banana = [math]b[/math]
[math]


w^{2} + w + (p \cdot a + s) = c \cdot b \\
w^{2} + w + (10 \cdot 4 + 1) = c \cdot b \\
w^{2} + 41w = cb \\
[/math]

Assuming [math]c \ne 0[/math]

[math]
\frac{w^{2} + 41w}{c} = b \\
b = \frac{w^{2} + 41w}{c} \\
[/math]

[math]
w = t_{1} \\
c = t_{2} \\
b = \frac{t_{1}^{2} + 41t_{1}}{t_{2}} \\


t_{1} \in \mathbb{R}, \\
t_{2} \in \mathbb{R}, t_{2} \ne 0 \\
[/math]

Just saw the restriction of [math]q, c, b \gt s[/math]

One solution with this in mind is [math]t_{1} = 420, t_{2} = 69 \\
w = t_{1} = 420 \\
c = t_{2} = 69 \\
b = \frac{w^{2} + 41w}{c} = \frac{420^{2} + 41(420)}{69} \\


[/math] (no restriction for integer values)
How'd I do?

>> No.11837664
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11837664

>>11837656
>using p,a,s instead of x,y,z

>> No.11837773

>>11835561
HOLY FUCK

>> No.11837784

>>11835561
I just solved this bros

But I ran out of a character limit for this post

>> No.11837840

>>11835148
It's actually a research level problem, so stop trying to solve it. It is indeed solved and involves the hyperbolic space if I remember correctly.

>> No.11838592

>>11835561
Clever, sadly 100% can't solve this one.

>> No.11838620

>>11838592
Andrew browses this board.

>> No.11839112

>>11835148
>5% success rate
I'm not a fucking retard, why would I waste time with this.