/sci/ - Science & Math

>>11659739
>MAAAAAMC

too fucking hard!

>>11659739
>doing math for competition
Pajeeet-tier

>>11659741
>multiple choice
So it's a test for brainlets.

These problems are boring.
1: Just calculate x, nothing complicated, and get 5/6.
2: (15*5-3-5-7)/2=30
3: Obviously -1
4: 60*(0.5-2/30)=26

>>11659744
Yeah these are too boring for me. Do them yourself.

Problems Increase in difficulty based on problem Number

>>11659785
Still all literal high school tier.
High school is to fuck hot teens, not do math.

Problems can be solved using brute force however it is adviced that analysis and pattern recognition be applied
Many of the problems are simpler than one thinks it just requires finding the pattern

>>11659795
>>11659785
Okay you are right. I tried 25 >>11659774 hoping it would be difficult. It's not that difficult but it took me quite some time to solve. Does this test have a time limit? If it's a time limit like only 1 hour, then the difficulty of the test is created by the time pressure, not the difficulty of the problems.

Give me like 5 hours and I will get all of them right for sure. If I only have 1 hour I probably will get only the first 15 or so of them.

Here's how I solved 25, took me more than 10 minutes.

Possible ways to get 7 are permutations of the sets (1,1,5),(1,2,4),(1,3,3),(2,2,3). Now the question is, when do we want to reroll exactly 2? The answer is when the probability of getting them right is higher than rerolling all 3 but lower than rerolling 1.

>reroll 2 instead of 1
When you have 2 right, the probability is always 1/6 for the last. The highest chance of rerolling two right is when you keep a 1, then the chance becomes 5/36 based on the sets above (1x3,3+2X2,4+2x1,5 /36) which is below 1/6. That means it is always better to reroll just 1 if you have already 2 correct.

>reroll 2 instead of 3
The chance of getting them right by rolling all 3 is the number of permutations of above sets, so 15/216=2.5/36. So to reroll 2, the number that we keep must have chance above that. Continuing from above, the chances are 4/36 for keeping 2, 3/36 for 3, 2/36 for 4 and 1/36 for 5. So rerolling 2 is only optimal if no more than 1 is right and we keep 1, 2 or 3.

>possibilities
From the above we get the following possibilities.
1 with 6s -> 3
2 with 5s and 6s -> 12
3 with 4s, 5s and 6s -> 27
27+3+12=42. 42/6=7 -> 7/36 is the correct answer.

My solution feels very brute forced. Is there a more elegant way to solve it that takes under 10 minutes?

>>11659792
I missed out on this and there's no going back.

>>11659920
Yep, there's no second chance. Literally one day you can fuck babes in the prime of their youth, virgins everywhere, all slutty, then the very next day you try that and you're a pedo sex offender. High school was your only chance. Try finding virgins older than 18, you won't. All used, all dumped, all on birth control and anti-depressants, hitting the wall with no exceptions.

You can do these meme math competition problems anytime. You can't fuck 10/10 16-17 yr olds once you turn a certain age.

>>11659895
Excellent!

If you would like more Intuitive problems rather than arithmetic work problems give us your vote

>>11659895
These are the Typical rules when taking the Test:

There are three Levels of the Test: Low Tier, Mid Tier, and Higher Tier, the test presented here is Mid Tier

75 Minutes
Passing Score: 100 pts
Perfect Score: 150 pts

Answering correctly: 6 pts
Answering incorrectly : 0 pts
No Answer: 1.5 Pts

No Calculator ( there was only one or two tests that allowed the use of Calculators)

>>11660387
>the test presented here is Mid Tier
>75 Minutes
>Passing Score: 100 pts
Heh. I am a STEM masters student and I fail a simple high school level test. Now I feel retarded.