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/sci/ - Science & Math


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10572609 No.10572609 [Reply] [Original]

>> No.10572615

there is no question posed. /thread


and if you don't like the clever answer, the forces balance. buoyant force is proportional to weight of displaced fluid. balls are same size. /thread x2

https://volafile org/r/w86qfmug

>> No.10572618

Fnet = 0

>> No.10572632

>>10572615
Thy Orbulon inquires which way the scale shall tip.

>> No.10572659

>>10572609
To the left, seeing as there is more unsupported mass in the left cup.

>> No.10572665

https://www.youtube.com/watch?v=QD3hbVG1yxM

>> No.10572670

>>10572609
ngl this op is kinda cringe bro tbqhwyf

>> No.10572685

>>10572615

wrong, the steel ball side will sink because the buoyant force on the right side is now supporting some of the mass that was supported by the string.

>> No.10572696

>>10572665
That surprised me

>> No.10572757
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10572757

>>10572609

>> No.10572759
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10572759

>>10572665

>> No.10572763
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10572763

>> No.10572765

>>10572757
>>10572759
>>10572763
Nobody would bother considering relativity for such a ridiculous problems. For all intents they weigh the same.

>> No.10572766
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10572766

>> No.10572769
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10572769

>> No.10572771
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10572771

>>10572765
DOUBT

>> No.10572773
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10572773

>> No.10572787

>>10572766
Wait, don't electrons weigh the same?

>> No.10572791
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10572791

>>10572773
A=B=C=(spec. weight of water)*(2 liters)=9.8 newtons

>> No.10572828

The left one because it weighs more.

>> No.10572835

>>10572773
Wouldn't A<B<C since the deeper you go the more pressure

>> No.10572841

>>10572757
On.
>>10572759
Yes.
>>10572763
A.

>> No.10572918

>>10572609
Steel ball weighs more, the buoyant force of the ping pong ball cancels out the pressure the ball would otherwise put on the water.

>> No.10572927

>>10572918
This is an IQ test not buoyancy physics test. You have to know the answer a priori.

>> No.10572935

>>10572927
Okay, and I just said the answer.
The buoyant force of the ping pong ball would cancel out the pressure the ball would otherwise put on the water.
I also said that the steel ball one weighs more.
Am I supposed to just answer randomly?

>> No.10572967

>>10572935

The steel ball one doesn’t weight more brainlet.

>> No.10573094

>>10572609
Assuming both balls have exactly the same volume and both vessels have exactly the same water level, the scale will tip to the left. The suspended steel ball is not contributing any net mass to the right container. However, if the weight of the ball is neglected, the right one would sink, since the left lacks a tiny amount of water because its string is longer (assuming the density of the string is lower than that of water). Hence the left one has less water volume and more string volume than the right one.

>> No.10573130

>>10572835
The pressure does increase, but the pressure differential over the water bottle is the same for A B and C so the force is constant over all of them.

>> No.10573157

>>10572773
it’s all the same force. buyance force is equal to volume displaced by bottle which isn’t changing

>> No.10573173

Oh shit idk. I'll say the ping pong side goes down because the ping pong ball has a little more mass. The steel mass does not push down the scales right?

>> No.10573188

>>10572757
The on bulb weights more. Because:
m = E / c^2

>> No.10573781

>>10572757
Electricity has weight, so on.

>> No.10573785

>>10572763
There's tiny switches that act as 1s and 0s right? So an empty and full harddrive weigh the same, bscause the same amount of switches, just in different settings.

>> No.10574284

>>10572967
There's a video explaining this problem somewhere on YouTube that I watched later on which confirms my statement, the buoyant force of the ping pong ball glass cancels out the pressure the ball would otherwise put on the water.
If you're gonna deny my statement, please state your own reason why.

>> No.10574308

>>10574284
Look at the system. You have a glass with water, a pingpong ball and a thread. If you look at it from the outside, it has the mass [math]m_\mathrm{tot} = m_\mathrm{glass} + m_\mathrm{ball} + m_\mathrm{thread}[/math]
I don't care about internal forces when I want to calculate the force, this system acts on the scale.

>> No.10574316

>>10574308
Yes, and I was giving an answer for what happens on the scale.
The lack of pressure from the ping-pong ball makes the glass equal the ping pong ball, the string, and the water.
The steel ball one puts pressure on the water that creates a push stronger than the ping pong ball, because the ping pong ball is also being pushed up due to the buoyant force in the water, which is why the string "stands up"
Therefore, the one with the steel ball weighs more.

>> No.10574353

>>10574316
I agree.

>> No.10574927

>>10572773
The only way A,B,C would be different i think is if the pressure would deform the bottle, compressing the air therefore displacing less water, so the buoyant force would be lower.

>> No.10576289
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10576289

>another IQ thread

>> No.10576452

>>10572609
Left has weight of water plus ball. Right has weight of water plus nothing. Buoyancy means shit because you can't pick yourself up by your feet. Left side is heavy.

>> No.10576498

The solution is a function of the size of the balls and weight of the ping pong ball.

1) force on right side: the water pressure is increased. The water pushes the heavy ball upwards, pushing the lever downward.

2) Weight on left side. Water pushes ping pong ball upwards, pushing lever downwards. However the string means the extra pressure counts for nothing.

1) But what about the weight of the ping pong ball? This is accounted for by less tension in the wire.

Conclusion: right side is weight of water+the weight of a ball full of water. Left side is weight of water + the ping pong ball.

>> No.10576890

>>10576289
based "another IQ thread" poster!