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/sci/ - Science & Math


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10076557 No.10076557 [Reply] [Original]

I need to show that [math]|x|<1[/math] iff [math]-1<x<1[/math].

PROOF

[math]|x|<1[/math]
iff [math]|x|<1 \wedge \top[/math]
iff [math]|x|<1 \wedge (x<0 \veebar x\geq 0)[/math]
iff [math](|x|<1 \wedge x<0)\veebar (|x|<1 \wedge x\geq 0)[/math]
iff [math](-x<1 \wedge x<0) \veebar (x<1 \wedge x\geq 0)[/math]
iff [math](-1<x \wedge x<0) \veebar (x<1 \wedge x\geq 0)[/math]
iff [math]-1<x<0 \veebar 0\leq x <1 [/math]
iff ...
iff [math]-1<x<1[/math].

How about the last step?
([math]-1<x<1[/math] means [math]-1<x \vee x <1[/math])

>> No.10076587

>>10076557
Retarded code monkey detected

>> No.10076679
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10076679

>>10076587
Complete the ... or back to the shadows where you belong.

>> No.10076765

>>10076557
* [math]-1<x \wedge x<1[/math].

>> No.10076772
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10076772

>>10076679
|x|<1 iff x<1 & -x<1 iff x<1 & -1<x iff -1<x<1

>> No.10077383
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10077383

>>10076772
What a mongoloid.
Your first step is what it is asked to be proved.