/sci/ - Science & Math

it's clearly 1, whoever you were arguing with is retarded

1^x = 1
therefore lim(1^x) as x-> inf
is equal to
lim(1) as x-> inf
which is just fucking 1

>>10054159
you could also write a silly proof like this too
lim(1^x) = lim((69^0)^x) = lim(69^(0*x)) = lim(69^0) = 69^0 =1

>>10054159
>I had an argument with a retard
Good 4U Anon

https://www.wolframalpha.com/input/?i=lim+1%5Ex+as+x-%3Einfinity

Probably meant (function that approaches 1)^(function that approaches infinity), as in the definition of e as a limit.

>>10054414
Yeah I think he might have gotten confused or something

>>10054414
Yeah, but he would still be wrong since [math]e[/math] is the limit.

>>10054159
If you let x approach infinity as the sequence 1, 2, 3,... then the limit is 1.
Let 1^(1/2) = -1
Letting x approach infinity as the sequence 1/2, 3/2, 5/2,... gives a limit of -1.

>>10055106
this guy's a brainlet

>>10055106
>Let 1^(1/2) = -1
topkek

>>10055106

>>10054162
It's fckin 0 you casual normalfags...
What fckin brainlets
Lim1/x with x to infinity makes the denominator either not defined but in our case working with limsit is zero...

>>10055546
[math] \frac{1}{x} \neq 1^{x} [/math]

>>10055587
lol brainlet

>>10054159
Yeah, you're right, that guys is retarded. Saying the limit of f(x) = 1^x is undefined is saying that the limit of f(x) = 1 is undefined. They're literally the same function.

>>10054164
>69
Nice

>>10055106
What exactly is wrong with this logic?

>>10057509
Ah fuck its a limit thats why, but the question is whats the limit of the complex evaluation of 1's roots to a rational number.

>>10054159
>this is what happens when physishits and other mathlets can’t into epsilon delta

it's whatever wolframalpha say