/sci/ - Science & Math

>AIDS
>doesnt even help you
What gives?

>>11590952
no
>>11591069
>current into page
>[math] \int B\cdot\text{d}s=0 [/math]
One of these is false. Circulation of B is proportional to the current enclosed.
>>11591509
>>11591623
literally just treat [math] \mathbf{u}\nabla [/math] as [math] (\nabla\mathbf{u})^T [/math]
>>11592709
imagine watching anime
>>11594309
The slope of the function y(x) at x=0
>>11593291
[math] \sin(10 t)\sin(400 t)=-.5\cos 410t+.5\cos 390t [/math]
use this https://download.cnet.com/Dual-Function-Generator/3000-2169_4-75717132.html and superimpose the two signals

Cable is parallel to the vector [math] \mathbf{u}=-1.6\mathbf{\hat i}+(0.7+0.8\sin 30^\circ)\mathbf{\hat j}+(1.2-0.8\cos 30^\circ)\mathbf{\hat k} [/math]. Now compute [math] \mathbf{\hat{u}}=\mathbf{u}/||\mathbf{u}|| [/math]. The maginitude of the force is 750 N. Therefore [math] \mathbf{F}=750\mathbf{\hat{u}} [/math]. The directions of the force are then [math]\theta_i=\arccos(\mathbf{\hat u}\cdot\mathbf{\hat e}_i) [/math] where e_i is each basis vector and theta_i is the angle between u hat and the relevant basis element.

Cable is parallel to the vector [math] \mathbf{u}=-1.6\mathbf{i}+0.7\mathbf{j}+(1.2-0.8)\mathbf{k}=-1.6\mathbf{i}+0.7\mathbf{j}+0.4\mathbf{k} [/math]. Now compute [math] \mathbf{\hat{u}}=\mathbf{u}/||\mathbf{u}|| [/math]. The maginitude of the force is 750 N. Therefore [math] \mathbf{F}=750\mathbf{\hat{u}} [/math]