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# /sci/ - Science & Math

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 >> A /sci/ Game Theory Challenge: 7-ballot inside joke  Anonymous Tue Nov 22 21:18:55 2022 No.15006670 [View] File: 52 KB, 609x788, Screenshot 2022-11-22 202226.jpg [View same] [iqdb] [saucenao] [google] There are 7 participants in this vote, who each get a ballot and are allowed to cast one vote for every contestant including themselves on their ballot. (So each ballot can be used to assign 7 votes and each vote is a point) The topic of the vote is negative and so the aim is to not get the highest number of votes. You do not want to win the vote. However, A and B have dared each other to try and get the highest vote. Everybody else is voting honestly. In other words, A and B are both competing with one another for the negative outcome and will use strategy, while everyone else will cast genuine ballots. For A and B winning is the most desired outcome. But both would rather draw than lose (So the expected outcomes are Win= 1 Draw= 0 and Losing= -1 for A and B). For the other 5 voters not winning is the most desired outcome. (Loss and draw= 1 and win= -1)So to make a Nash Equilibrium between A and B possible we will assume that the only contestants able to vote for themselves are A and B, and nobody else will vote for themselves, as they do not want to give themselves a point. However, everyone else can be assumed to cast a random ballot other than that. So, another contestant can make any possible combination of votes as long as it does not include their own name.So... How would A and B distribute their votes to achieve Nash Equilibrium?I am sorry if this was not explained clearly. If not I will clear anything up. The immediate common sense answer I had was that A casts a vote for A and B casts a vote for B, leaving the rest up to chance. But when I tried to work this out and prove it I realized that this problem filtered me hard. So I would love to see how you guys approach this.

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