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/sci/ - Science & Math

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>> No.7934635 [View]
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7934635

>>7933729
no
[math] \displaystyle f(2) = \sum_{n=0}^{\infty} \frac{2^n}{2^n} = \sum_{n=0}^{\infty}1[/math]
[math] \displaystyle \sum_{n=0}^{\infty} 1 = 1 + \sum_{n=1}^{\infty}1 [/math]
[math] \displaystyle 1 + \sum_{n=1}^{\infty} 1 = 1+ \sum_{n=1}^{\infty} \frac{1}{n^0} = 1 + \zeta(0) = 1 + (-\frac{1}{2}) = \frac{1}{2}[/math]

>> No.7666892 [View]
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7666892

there are more large numbers than small numbers
so statistically, there is more chance of a large number being interesting
because there are more

>> No.7541965 [View]
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7541965

We are given <span class="math">U_n = (\frac{7}{10})^{n^2}[/spoiler]

we simply exponentiate to remove the n from subscript

<span class="math">U_n^n = U = (({\frac{7}{10})^{n^2})}^n = \frac{7}{10}^{n^3}[/spoiler]

now to find the direction of change, we take the derivative

<span class="math">\frac{d}{dx} U = \frac{d}{dx}\frac{7}{10}^{n^3} = -\infty[/spoiler]

here we come to the conclusion that the direction in which this sequence is changing is beyond human comprehension

>> No.7144261 [View]
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7144261

whenever you see "integral" it's usually short for integral domain, where integral is the adjectival form of integer (a ring of integers or integer like objects)
triple integrals are three dimensional integral domains, which is why so few people know how to solve them
i advise you search the internett before you create threads like this

>> No.7094790 [View]
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7094790

let's try to figure this out

>personality type
>colors

INTJ
blue & black

>> No.7070155 [View]
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7070155

25 has the interesting property that for any real number x less than 25, it can be shown that 25 is greater than x

>> No.7014074 [View]
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7014074

>>7014011
No, the proof is fine. It perfectly discredits what it was intended to discredit; a particular notion of "scaling up" quantum mech to macros scales.

Of course the Geiger counter would cause collapse. But that isn't the problem Schrodinger was trying to address. No one has a problem with the wave function collapse from a Geiger counter. The experiment becomes trivial.

>> No.6628139 [View]
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6628139

the wool holds a lot of air, but the steel doesn't
the wool side is heavier

>> No.6574729 [View]
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6574729

assuming the circles are tangent and have radius 1, the best fitting circle has radius 2sqrt(3)/3 + 1

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