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>> No.10209002 [View]
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10209002

Tell me what I'm doing wrong sci:

Let x = 1/y, then log(1+x) = -log(1/(1+x)) = -log(y/(y+1)). Let Y be near 0. The linear approximation for y/(y+1) is y. So,
log(y/(y+1)) [math]\approx[/math] log(y), i.e.
log(1+x) [math]\approx[/math] -log(y) = log(x).

But this should only work when x is small. x is big here since y is small.

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