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>> No.10377162 [View]
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10377162

>>10376057
[math]||T|| \geq 2[/math] because you can look at vector [math][1, 0][/math]
[math]||T|| \leq 2[/math] because [math]\sqrt{4a^2 + b^2} \leq \sqrt{4a^2 + 4b^2} = 2 \sqrt{a^2 + b^2} [/math]

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