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>> No.4201846 [DELETED]  [View]
File: 372 KB, 1944x2896, 1302822015146.jpg [View same] [iqdb] [saucenao] [google]
4201846

Austrian, currently working in Germany-anon here.

I'd like to study in Munich or France one day.

(Then of course the good universities in england sound nice too, because they speak englisch. And Even I guess there are some very very good people in USA too, so I'd also like to study there)

>> No.3907787 [View]
File: 372 KB, 1944x2896, 1302822015146.jpg [View same] [iqdb] [saucenao] [google]
3907787

>>3907645
the first line implies that D_\mu u^\mu=0 which will not be true for an arbitrary vector field. And as I said before, you would not take a spatial derivative of the for vector of a trajectory - this trajectory is just a string in spacetime.

And the other two lines make no sense. what is

int f(y^\mu) dy?
what is y in dy here? if it's a parameter, then what is y\mu?

Is f(x\mu) a vector field, like

W = (f(t),f(x),f(y),f(z))

I've never seen this construction before.

>>3907715
>not into blondes
you're werd

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