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>> No.15038541 [View]
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15038541

>>15038350
I haven't done group theory in a while so this might be completely retarded but isn't the order of the normalizer the order of [math]G[/math] divided by how many conjugates [math]H[/math] has in [math]G[/math]?
Which should be, combinatorially, the number of ways you can split [math]\{ 1, 2, 3, 4, 5, 6 \}[/math] into three sets with two elements each (I might be wrong but I think transpositions were only conjugate with other transpositions, which would trivialize this part).

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