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/sci/ - Science & Math

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>> No.11146413 [View]
File: 137 KB, 1003x323, Screen Shot 2019-11-14 at 10.19.31 AM.png [View same] [iqdb] [saucenao] [google]
11146413

>>11146319
Pic related is the problem. I just do NOT understand how the first term is squared. I can only arrive at the same solution but with only the numerator squared, not the denominator.

It's just a complete the square problem, so I get:
[math] \frac{b^2}{a} - \frac{4c}/{a} [/math], I don't know how I'm supposed to get (b/a)^2.

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