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>> No.15078411 [View]
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15078411

>>15076783
>>15076786
Yeah, since the set of all finite sequences of elements of a countable set is also countable.
>>15077560
No.
But you can show that [math]\exp (ax)[/math], [math]a \in \mathbb{R}[/math] are all linearly independent because they're all eigenvectors of the differential operator with different eigenvalues.
>>15078064
Pretty sure I pick Cirno fairly often for the OP.

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