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>> No.2749397 [View]
File: 132 KB, 600x600, timetravel.jpg [View same] [iqdb] [saucenao] [google]
2749397

Not OP, but bumping with an answer.

>"Train, moving in one direction has a velocity equivalent of 0.5 kelvin

By the Unruh equation,

<span class="math">T = \frac{\hbar a}{2 \pi c_0 k_b} \approx (4.055 \cdot 10^{-12} K) \frac{a}{m/s^2}[/spoiler]

Thus in order for T = 0.5 K, the train must posses an acceleration of <span class="math">a = 1.223 \cdot 10^{12} {m/s^2}[/spoiler] and so we take the instantaneous velocity as the velocity of the train:

<span class="math">v = (a) \; dt = 1.223 \cdot 10^{12} {m/s} \approx 411 \, c_0[/spoiler]

So now we know that the train is moving faster than the speed of light.

> bullet's mass is 12.67g. bullet's velocity is (train's velocity * 1/0.05K) and height from ground 50cm.

So the bullet's velocity via the equation given is:

<span class="math">v_b = 411 \, c_0 \, \frac{1}{0.05} = 8226 \, c_0[/spoiler]

I ignored the kelvin units because your teacher is dumb and I don't like them. The momentum of the bullet is <span class="math">p_b =12.67 g \, v_b = 3.125 \cdot 10^{10} \, {kg \; m/s}[/spoiler]

If we assume that there is an infinite surface 50cm below the bullet, which has a surface gravity of 9.8 m/s^2, then of crouse as the bullet travels it will experiance an energy decrease over time. HOWEVER, becaseu we have established that the bullet is a tachyon, the math from relativity thoery tells us that as the energy of the bullet decreases, it's speed increases.

So presumably, the bullet will travel forever at an infinitely great speed. Bust mostly, the bullet is just travelling backwards in time.

>> No.1005212 [View]
File: 132 KB, 600x600, timetravel.jpg [View same] [iqdb] [saucenao] [google]
1005212

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