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>> No.8097179 [View]
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8097179

For my complementary functions I get
x = A exp(it)
y = B exp(it)

And for the particular integrals I guess
x = at + b
y = ct + d

But this results in the general solution
x = A exp(it)
y = t + B exp(it)
Which makes the solutions obtained from the boundary conditions inconsistent with the original equations. I'll humour them a second:
t = 0, x = 0, y = 1
A = 0 -> x = 0
B = 1 -> y = t + exp (it)

Back in the first equation:
0 + 1 + i exp (it) + 0 = 1
Which means i exp (it) = 0...

I have no idea where I went wrong. Help! Exams are in two weeks...

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