/sci/ - Science & Math

I know that the number of jordon blocks associated with an eigenvalue is equivalent to it's respective eigenspace dimension. I also know that the dimension of the eigenspace is less than or equal to the algebraic multiplicity of the eigenvalue. Since we have three distinct eigenvalues, we can have one with multiplicity two, and rest must be one. So does that mean that there are 4 possible jordan canonical forms up to permutation?