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>> No.15658917 [View]
File: 61 KB, 292x302, wwydt.jpg [View same] [iqdb] [saucenao] [google]
15658917

>>15658850
> I wanted to solve f(x) = x^2 without doing its exponent.
What does that even mean??

I can't follow your derivative argument at all, but you did (accidentally?) come up with the following:
> (1+2+3+4+5) is a triangular sum
And the formula for that sum is [math]T_n = \dfrac{n(n+1)}{2}[/math]. In your argument [math]n = x - 1[/math], so
[eqn]2 T_{x-1} + x = 2 \dfrac{(x-1)(x - 1 +1)}{2} + x = x(x-1) + x = x^2[/eqn]

I have no idea how you are expecting to calculating a series sum without knowing how long it is (x).

>> No.11880234 [View]
File: 62 KB, 292x302, 1337585540917.jpg [View same] [iqdb] [saucenao] [google]
11880234

>>11880227
Yep, it was bait.

>>11880229
Looks like it is true lmao.

>> No.7604990 [View]
File: 80 KB, 292x302, Why would you do that.jpg [View same] [iqdb] [saucenao] [google]
7604990

>>7604935
>6.EditorVi(oEMACS) 8hrs

Fucking autistics refusing to acknowledge that the computer mouse and UI exist and stuck in the 70s

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