[ 3 / biz / cgl / ck / diy / fa / ic / jp / lit / sci / vr / vt ] [ index / top / reports ] [ become a patron ] [ status ]
2023-11: Warosu is now out of extended maintenance.

/sci/ - Science & Math

Search:


View post   

>> No.10749733 [View]
File: 1.01 MB, 1280x1280, 1561068869425.jpg [View same] [iqdb] [saucenao] [google]
10749733

>>10749531
weight one= water+pingpong weight
weight 2= water + buoyancy force of sphere

Since in the second flask the metallic sphere is not moving, we can assume it's forces are at equilibrium meanign that
Force from steel weight= buoyancy force + pull from string
That means that the buoyancy force from the steel sphere is canceled out from the weight of the steel ball and from newton's first law since every action has an equal and opposite reaction the reactionary buoyancy force on the steel ball is still acting on the flask pushing it down. This is in contrast to the first flask where the buoyancy forces are all canceled out.

Since Ping Pong balls float, assuming that booth balls have the same volume, that means that the reactionary buoyancy force on the second flask is greater than the weight on from the ping pong ball in the first flask.

Which means that the second flask should tip down.

I dunno wheter I'm right or not, please correct.

Navigation
View posts[+24][+48][+96]